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4 years ago

7

33x-21x=-24+12 I need help on this math problem. Thanks

1 answer:

lions [1.4K]4 years ago

8 0

X=3. 33x-21x equals 12x. 24+12=36. 12x divided by 36 equals 3

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Write the equation of the parallel line that passes through (0,-3)

Gemiola [76]

Answer:

y = 1.2x - 3 (slope intercept form)

or

5y-6x = -15 (standard form)

Step-by-step explanation:

Two parallel lines have the same slope, which means that our line's slope, will also be 1.2.

we can use the formula to find the equation of the line:

y-y1 = m (x-x1)

y1 - y coordinate of a point on the line

x1 - x coordinate of the same point on the line

m - slope

and we get:

y+3 = 1.2 (x-0)

y = 1.2x - 3 (slope intercept form)

or

5y-6x = -15 (standard form)

5 0

3 years ago

Can someone please help me on this

Tanzania [10]

$a=2(-2)-1 = -4-1 =-5\\\\b=2(-1)-1 = -2 - 1 = -3\\\\c=2(1)-1 = 2-1 = 1\\\\d=2(2) -1 = 4 -1 =3$

7 0

2 years ago

The equation tan(x- pi/3) is equal to _____.

kherson [118]

Answer:

B

Step-by-step explanation:

Using the expansion

tan(x - y) = $\frac{tanx-tany}{1+tanxtany}$ , then

tan(x - $\frac{\pi }{3}$ )

= $\frac{tanx-tan(-\frac{\pi }{3}) }{1+tanxtan(-\frac{\pi }{3}) }$

note that tan( - $\frac{\pi }{3}$ ) = - tan( $\frac{\pi }{3}$ ) = - $\sqrt{3}$

= $\frac{tanx-(-\sqrt{3}) }{1+tanx(-\sqrt{3}) }$

= $\frac{tanx+\sqrt{3} }{1-\sqrt{3}tanx }$ → B

6 0

3 years ago

Read 2 more answers

HELP WITH ALL <br> Determine the composite functions of the following set of functions

elixir [45]

QUESTION 1

i) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(f\circ g)=f(g(x))$

$(f\circ g)=f(x^2)$

We plug in $x^2$ into $f(x)=5x-2$

$(f\circ g)=5x^2-2$

ii) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(g\circ f)=g(f(x))$

$(g\circ f)=g(5x-2)$

We plug in $5x-2$ into $g(x)=x^2$

$(g\circ f)=(5x-2)^2$

$(g\circ f)=25x^2-10x-10x+4$

$(g\circ f)=25x^2-20x+4$

QUESTION 2

i) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(h\circ g)=h(g(x))$

$(h\circ g)=h(x^2-4)$

We plug in $x^2-4$ into $h(x)=\sqrt{2x+1}$

$(h\circ g)=\sqrt{2(x^2-4)+1}$

$(h\circ g)=\sqrt{2x^2-8+1}$

$(h\circ g)=\sqrt{2x^2-7}$

ii) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{2x+1})$

We plug in $\sqrt{2x+1$ into $g(x)=x^2-4$

$(g\circ h)=(\sqrt{2x+1})^2-4$

$(g\circ h)=2x+1-4$

$(g\circ h)=2x-3$

QUESTION 3

i) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{x-4})$

We plug in $\sqrt{x-4}$ into $g(x)=x+5$

$(g\circ h)=\sqrt{(x-4)+5}$

ii) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ g)=g(g(x))$

$(g\circ g)=g(x+5)$

We plug in $x+5$ into $g(x)=x+5$

$(g\circ g)=(x+5)+5}$

$(g\circ g)=x+10}$

QUESTION 4

The given functions are;

$f(x)=-2x+1$ and $g(x)=-x^2$

$f\circ f=f(f(x))$

$f\circ f=f(-2x+1)$

$f\circ f=-2(-2x+1)+1)$

$f\circ f=4x-2+1)$

$f\circ f=4x-1)$

ii)

$g\circ g=g(g(x))$

$g\circ g=g(-x^2)$

$g\circ g=-(x^2)^2$

$g\circ g=-x^4$

QUESTION 5

$f(x)=5x-2;g(x)=x^2;h(x)=-3x$

$h\circ g\circ f=h\circ (g(f(x))$

$h\circ g\circ f=h\circ (g(5x-2))$

$h\circ g\circ f=h\circ ((5x-2)^2)$

$h\circ g\circ f=h\circ (25x^2-20x+4)$

$h\circ g\circ f=h(25x^2-20x+4)$

$h\circ g\circ f=-3(25x^2-20x+4)$

$h\circ g\circ f=-75x^2+60x-12)$

ii.

$f\circ f\circ g=f\circ (f(g(x))$

$f\circ f\circ g=f\circ (f(x^2)$

$f\circ f\circ g=f\circ (5x^2-2)$

$f\circ f\circ g=f(5x^2-2)$

$f\circ f\circ g=5(5x^2-2)-2$

$f\circ f\circ g=25x^2-10-2$

$f\circ f\circ g=25x^2-12$

7 0

3 years ago

What set of numbers list the factors of 32

ser-zykov [4K]

That would be b

hope this helps

3 0

3 years ago

Read 2 more answers