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2 years ago

What is the domain of the function graphed below?

Mathematics

1 answer:

WITCHER [35]2 years ago

5 0

From the graph, the domain of the function will be {x| x = −2,1}. Then the correct option is D.

<h3>What is an asymptote?</h3>

An asymptote is a line that constantly reaches a given curve but does not touch at an infinite distance.

From the graph, the domain of the function will be

The function is not defined for x = 2 and x = -1.

Then the domain will be

{x| x = −2,1}

Then the correct option is D.

More about the asymptote link is given below.

brainly.com/question/17767511

#SPJ1

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Simplify the expression (6+2)^2-4×3 using the order of operations((the 2 is an exponent))

jasenka [17]

The answer is -767/64

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3 years ago

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A sum of money is shared between Ali and

Zarrin [17]

Answer:

Ben' share = 2(600/5) = $240

Step-by-step explanation:

Let the sum of money be x

Given that the ratio between Ali and Ben is 3:2

As adding both parts of ratio gives 5 parts so,

For finding one part = x/5

So according to given condition:

Ali's share(one part) + Ben's share(one part) = 120

3(x/5) - 2(x/5) = 120

By simplifying:

x/5 = 120

Multiplying both sides by 5

x = 600

So the total amount is 600

Ali's share would be = 3(600/5) = $360

Ben' share = 2(600/5) = $240

i hope it will help You!

6 0

3 years ago

Which list contains only values equivalent to 3/10

bekas [8.4K]

Answer:

Step-by-step explanation:

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2 years ago

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Ms. Bruckner sells a car for $16,400. How much does she earn with a 1.4% commission?

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7 0

3 years ago

Find the exponential function that passes through the points (2,80) and (5,5120)

juin [17]

Answer:

y = 5·4^x

Step-by-step explanation:

If you have two points, (x1, y1) and (x2, y2), whose relationship can be described by the exponential function ...

y = a·b^x

you can find the values of 'a' and 'b' as follows.

Substitute the given points:

y1 = a·b^(x1)

y2 = a·b^(x1)

Divide the second equation by the first:

y2/y1 = ((ab^(x2))/(ab^(x1)) = b^(x2 -x1)

Take the inverse power (root):

(y2/y1)^(1/(x2 -x1) = b

Use this value of 'b' to find 'a'. Here, we have solved the first equation for 'a'.

a = y1/(b^(x1))

In summary:

b = (y2/y1)^(1/(x2 -x1))
a = y1·b^(-x1)

For the problem at hand, (x1, y1) = (2, 80) and (x2, y2) = (5, 5120).

b = (5120/80)^(1/(5-2)) = ∛64 = 4

a = 80·4^(-2) = 80/16 = 5

The exponential function is ...

y = 5·4^x

3 0

3 years ago