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Mrac [35]
3 years ago
15

What is the solution to the equation -4x-12=-11x+23

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0
-4x-(-12)=(-11x)+23
       +12             +12
-4x=(-11x)+35
+11x  +11x
 7x=35
 /7  /7
 x=5  

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One tray holds eight sandwiches if there are 30 sandwiches in all, how many trays are needed?
nika2105 [10]
30/8=3.75
So, you need 4 trays, since you can't have 75% of a tray.
Hope this helps
3 0
3 years ago
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The population of a town can be modeled by P= 22,000 + 125t, where P represents the population and the t represents the number o
nlexa [21]
Given that the population can be modeled by P=22000+125t, to get the number of years after which the population will be 26000, we proceed as follows:
P=26000
substituting this in the model we get:
26000=22000+125t
solving for t we get:
t=4000/125
t=32
therefore t=32 years
This means it will take 32 years for the population to be 32 years. Thus the year in the year 2032
7 0
3 years ago
Out of 30 problems on the test jose got 4 wrong. What percentage did jose get correct?
dedylja [7]
Jose got 80% correct 
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What’s 3/4 x 22/7 x 2
Zolol [24]

Answer:

4\frac{5}{7}

Step-by-step explanation:

we just multiply numerator by numerator and denominator by denominator

3/4x22/7

66/28x2/1

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3 0
1 year ago
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Solve the rational function of (check image) and check for extraneous solutions
Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

\frac{5}{x}=\frac{4x+1}{x^2}

Solving the rational function

\frac{5}{x}=\frac{4x+1}{x^2}

Apply fraction across multiply: if \frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5x^2=x\left(4x+1\right)

Subtract x(4x+1) from both sides

5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)

Simplify

5x^2-x\left(4x+1\right)=0

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

so

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x=0\quad \mathrm{or}\quad \:x-1=0

Thus, the solution to the equation is:

x=0,\:x=1

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0
3 years ago
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