If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
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Congruent since all angles are equivalent to each other.
A, C, D are the correct answers.
-5 is neither a whole number nor a natural number. This is because negative numbers are not included in these. Hope this helps! Let me know:)
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Answer:
HCF=2*2=4
Step-by-step explanation:
Given : Shane wants to plant 28 marigold plants and 36 rose plants in his garden
To Find : the greatest number of rows possible each row has the same
number of marigold plants and the same number of rose plants.
Solution:
marigold plants = 28
rose plants = 36
To find the greatest number of rows possible if each row has the same
number of marigold plants and the same number of rose plants.
we need to find HCF of 28 and 36
28 = 2 x 2 x 7
36 = 2 x 2 x 3 x 3
HCF = 2 x 2 = 4
greatest number of rows possible is 4
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