Answer:
square inches.
Step-by-step explanation:
<h3>Area of the Inscribed Hexagon</h3>
Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be
inches (same as the length of each side of the regular hexagon.)
Refer to the second attachment for one of these equilateral triangles.
Let segment
be a height on side
. Since this triangle is equilateral, the size of each internal angle will be
. The length of segment
.
The area (in square inches) of this equilateral triangle will be:
.
Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:
.
<h3>Area of of the circle that is not covered</h3>
Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is
inches, the radius of this circle will also be
inches.
The area (in square inches) of a circle of radius
inches is:
.
The area (in square inches) of the circle that the hexagon did not cover would be:
.
Answer:
Cos θ = -4/5
Tan θ = -3/4
Step-by-step explanation:
The question is as following:
Select the correct answer from each drop-down menu.
Angle θ lies in the second quadrant, and sin θ =3/5.
cos θ = -4/5, -3/5, 3/5, 4/5
tan θ = -4/3, -3/4, 3/4, 4/3
==================================================
Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.
If sin θ =3/5

∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.
And
Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.
Answer:
C= 7y +150
850
250
Step-by-step explanation:
The cost is 7 times y, the number of yearbooks, plus 150, the upfront cost.
7 times 100 is 700, plus 150 is 850.
1900-150 is 1750 divided by 7 is 250