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san4es73 [151]
2 years ago
8

What is the point (-9,-3) after rotating 180 counterclockwise

Mathematics
1 answer:
sleet_krkn [62]2 years ago
4 0

Answer:

(9, 3)

Step-by-step explanation:

When a point is rotated 180 degrees, you take the opposite of the coordinates.

i.e (5, 6) ---> (-5, -6)

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the
Brrunno [24]

Answer:

\left(100\pi - 150\sqrt{3}\right) square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be 10 inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment \sf CH be a height on side \sf AB. Since this triangle is equilateral, the size of each internal angle will be \sf 60^\circ. The length of segment

\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}.

The area (in square inches) of this equilateral triangle will be:

\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}.

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}.

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is 10 inches, the radius of this circle will also be 10 inches.

The area (in square inches) of a circle of radius 10 inches is:

\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi.

The area (in square inches) of the circle that the hexagon did not cover would be:

\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}.

3 0
3 years ago
Select the correct answer from each drop-down menu.
Ahat [919]

Answer:

Cos θ  = -4/5

Tan θ = -3/4

Step-by-step explanation:

The question is as following:

Select the correct answer from each drop-down menu.

Angle θ lies in the second quadrant, and sin θ =3/5.

cos θ = -4/5, -3/5, 3/5, 4/5

tan θ = -4/3, -3/4, 3/4, 4/3

==================================================

Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.

If sin θ =3/5

cos \  \theta =\sqrt{1-sin^2 \theta} = \sqrt{1-(\frac{3}{5} )^2} =\sqrt{1-\frac{9}{25} }=\sqrt{\frac{16}{25} } =\frac{4}{5}

∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.

And

Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.

3 0
3 years ago
Solve: 2x-10= 40<br>Solve for X​
Arturiano [62]
The correct answer is B
4 0
2 years ago
Read 2 more answers
Step by step explanation thanks
Inessa [10]

Answer:

C= 7y +150

850

250

Step-by-step explanation:

The cost is 7 times y, the number of yearbooks, plus 150, the upfront cost.

7 times 100 is 700, plus 150 is 850.

1900-150 is 1750 divided by 7 is 250

7 0
3 years ago
Read 2 more answers
Translate the triangle left 1 units and up 5 units. What are the coordinates of point C after the translation?
Step2247 [10]

Answer:

b++nfr

Step-by-step explanation:

jjkiki

5 0
3 years ago
Read 2 more answers
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