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3 years ago

What is 18.386 rounded to the nearest Hundred

Mathematics

1 answer:

jonny [76]3 years ago

8 0

This will be 18.39, 6 is higher than 5, so the 8 is going higher so it's a 9 and you will get 18.39

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El cuadruple de un numero mas un quinto

11Alexandr11 [23.1K]

4x+1/5
I hope this helps! I'm hoping google translated your question properly, I'm native english speaking
¡Espero que esto ayude! Espero que google tradujera tu pregunta correctamente, soy nativo de habla inglesa

4 0

3 years ago

Explain the connection between factors of a polynomial, zeros of a polynomial function, and solutions of a polynomial equation.

MrRissso [65]

Answer:

Step-by-step explanation:

Solutions, zeros, and roots of a polynomial are all the same exact thing and can be used interchangeably. When you factor a polynomial, you solve for x which are the solutions of the polynomial. Since, when you factor a polynomial, you do so by setting the polynomial equal to 0, by definition of x-intercept, you are finding the zeros (don't forget that x-intercepts exist where y is equal to 0). There's the correlation between zeros and solutions.

Since factoring and distributing "undo" each other (or are opposites), if you factor to find the zeros, you can distribute them back out to get back to the polynomial you started with. Each zero or solution is the x value when y = 0. For example, if a solution to a polynomial is x = 3, since that is a zero of the polynomial, we can set that statement equal to 0: x - 3 = 0. What we have then is a binomial factor of the polynomial in the form (x - 3). These binomial factors found from the solutions/zeros of the polynomial FOIL out to give you back the polynomial equation.

8 0

3 years ago

With a family bowling pass, families can bowl for $4 per game . The pass cost $10 per year. Use equation , a table and a graph t

Klio2033 [76]

Answer:

Part a) $a=4g+10$ (see the explanation)

Part b) see the explanation

Part c) The graph in the attached figure

Step-by-step explanation:

<u><em>The complete question is</em></u>

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

a ----> the total amount of money spent on bowling in a year

g ---> the number of games a family plays in a year

we know that

The linear equation in slope intercept form is equal to

$a=mg+b$

where

m is the slope or unit rate

b is the a-intercept or initial value

In this problem we have

$m=\$4\ per\ game$

$b=\$10$

substitute

$a=4g+10$

Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> $a=4(0)+10=\$10$

For g=1 ----> $a=4(1)+10=\$14$

For g=2 ----> $a=4(2)+10=\$18$

For g=3 ----> $a=4(3)+10=\$22$

For g=4 ----> $a=4(4)+10=\$26$

The table is

$\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]$

Part c) Use the values from your table to draw a graph

we have the ordered pairs

$(0,10),(1,14),(2,18),(3,22),(4,26)$

Plot the ordered pairs and join them to graph the line

The graph in the attached figure

6 0

3 years ago

Also this is apart of it

yawa3891 [41]

Ya awesome keep up the great work ❤️❤️❤️

6 0

3 years ago

What is a mixed number for 5/2

m_a_m_a [10]

Answer: 2 1/2

Step-by-step explanation: Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction. Hope this helps!! PLZ mark me!!!

8 0

3 years ago