Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Write them in order from least to greatest,
11.9, 12.0, 12.3, 12.4, 12.4, 12.5, 12.7,12.8, 12.9, 13.1, 13.2, 13.8
then eliminate one from each side until you find the middle one,
12.5, 12.7
you have two middle, so you find the middle number in between them.
12.6 is the median.
I'm assuming you mean 2^(5)(4/3)(2).
So multiplying all of the powers together yields 2^(40/3)
Answer: (a) $6,600
(b) $28,600
<u>Step-by-step explanation:</u>
Interest (I) = Principal (P) x rate (r) x time (t)
I = 22,000(0.06)(5)
= 6,600
Accrued (A) = Principal (P) + Interest (I)
A = 22,000 + 6,600
= 28,600