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ycow [4]
3 years ago
13

Find the sum of the first 325325 positive even whole numbers.

Mathematics
1 answer:
iris [78.8K]3 years ago
6 0
Multiply 325326×(325325/2)=52,918,503,138 How it works:
know that 325325+1 is 325326, then 325324+2 is the same number, therefore you will get this number as many times as half of biggest number since you sum every last biggest number-1 with every last smallest number+1. so just multiply and you will get
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Which relationship between x and y in the equation shows a proportional relationship
balandron [24]

Answer:

The equation y = 3x shows a proportional relationship between x and y

Step-by-step explanation:

  • <em>The proportional relationship is represented graphically by a line passes through the </em><em>origin point </em>
  • <em>The equation of the proportional relationship is </em><em>y = m x</em>

Let us solve the question

Substitute x by 0 to find the value of y, if y = 0, then the line represents this equation passes through the origin point, then the equation shows a proportional relationship

∵ y = 3x

∵ x = 0

∴ y = 3(0)

∴ y = 0

→ That means the line that represents the equation passes through

   the origin point

∴ The equation y = 3x shows a proportional relationship between x and y

7 0
3 years ago
Express the number 68,708 in word form and expanded form.<br><br> Word form ?<br> Expanded form ?
Alenkinab [10]
Sixty eight thousand seven hundred and eight in word form

60000+8000+700+8 in expanded form
8 0
1 year ago
With full explanation from the internet like before<br> 3x2-6x+5=0
Elodia [21]

Answer:

\sf x=1+i\sqrt{\dfrac{2}{3}}   \ \quad and  \quad \:x=1-i\sqrt{\dfrac{2}{3}}

Explanation:

<u>Given Expression</u>:

  • 3x² - 6x + 5 = 0

Use the Quadratic Formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \  \ when   \ \  ax^2 + bx + c = 0

<u>insert coefficients</u>

\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}

\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}

\Longrightarrow \sf x =1 \pm   i\dfrac{\sqrt{6} }{3}

\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}},  \quad 1-i\sqrt{\dfrac{2}{3}}

6 0
2 years ago
Read 2 more answers
please help i am failing math class she said if you dont turn in this Backpack artifact task am going to fail it is 6th grade ma
agasfer [191]

Answer:

I might be able to help as long as there's no algebra involved

6 0
2 years ago
Read 2 more answers
I can't figure out how to do <br> -5+x/3=-11
-BARSIC- [3]
Add 5 to both sides
5-5+x/3=5-11
0+x/3=-6
x/3=-6
times both sides by 3
3x/3=-18
x=-18
3 0
3 years ago
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