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Hunter-Best [27]
2 years ago
11

Which expression is three less than the product of a number and two,increased by five

Mathematics
1 answer:
Tpy6a [65]2 years ago
6 0

Answer:

(2x+5)-3

Step-by-step explanation:

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Carter has one 20$ bill, one 10$bill, four 5$ bills and two 1$ bill,Aubrey has two 10$bills ,five 5$ bills and seven 1$ bills .w
Luba_88 [7]
Carter- 20+10=30+(5x4)=50+2=$52
Aubrey- 10x2=20+(5x5)=45+7=$52
They both have the same amount of money
8 0
3 years ago
Read 2 more answers
Work this out by giving your answer as a fraction 2/3 - 1/2
suter [353]

When subtracting fractions, you need to make sure the denominators are the same. In 2/3 - 1/2, the denominators are different. To make them the same, find the least common denominator. In this case, the common denominator is 6

2/3 becomes 4/6

1/2 becomes 3/6

Now subtract the fractions with the common denominator

4/6 - 3/6 = 1/6

The answer is 1/6

Hope this helps. Please mark me as Brainliest. Thanks!

7 0
2 years ago
Read 2 more answers
What is x in 832 = 2( 7.5x + 39)
ziro4ka [17]

Answer:

5 rolls is the answer

6 0
4 years ago
Read 2 more answers
2. XYZW is a parallelogram with diagonals XZ and YW that intersect at point A.
sergeinik [125]

Answer:

AW=10

Step-by-step explanation:

In a parallelogram opposite sides are congruent meaning XA and AZ are congruent. YA and AW are congruent. So...

Solving for XA and AZ

 XA=AZ

3m=5m-4

-2m=-4

m=2

If YW=10m then 10 x 2 = 20

20 divided by 2 = 10

4 0
3 years ago
The lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 h
DaniilM [7]

Answer:

Probability that a battery will last more than 19 hours is 0.0668.

Step-by-step explanation:

We are given that the lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 hours.

<em>Let X = lifetime of a battery in a certain application</em>

So, X ~ N(\mu=16,\sigma^{2} =2^{2})

The z-score probability distribution for normal distribution is given by;

               Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean lifetime = 16 hours

            \sigma = standard deviation = 2 hours

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a battery will last more than 19 hours is given by = P(X > 19 hours)

  P(X > 19) = P( \frac{  X -\mu}{\sigma} > \frac{19-16}{2} ) = P(Z > 1.50) = 1 - P(Z \leq 1.50)

                                              = 1 - 0.9332 = 0.0668

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.</em>

Hence, the probability that a battery will last more than 19 hours is 0.0668.

5 0
3 years ago
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