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MariettaO [177]
2 years ago
13

Tom exercise a total of 150 minutes in two days he exercise 20 minutes less on the first day then on the second day how many min

utes did he exercise each day?
Mathematics
2 answers:
Viktor [21]2 years ago
7 0
Answer 65 and 85 minutes
Reason
We know he exercised for 2 days
We know the second day was -20
We know the total minutes = 150
We don’t know x

Equation is 2x -20 = 150. Solve for x
Isolate x by subtracting (-20) from both sides.
2x = 170. Solve for x by dividing both sides by 2.
X= 85
Now we know the first day was (-20)
85-20= 65

Answer 85 + 65 = 150
elixir [45]2 years ago
6 0

Answer:

60 on the first day and 80 on the second

Step-by-step explanation:

the first day was lesser than the second day by 20 minutes.

so the second day was more than the first day by 20 minutes.

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Let a= x2 +4 rewrite the following equation in terms of a and set it equal to zero. (X2 + 4)2 + 32 = 12x2 + 48 in the resulting
Alex73 [517]
Answer: \\ {( {x}^{2} + 4) }^{2} + 32 = 12 {x}^{2} + 48 \\ \Leftrightarrow {a}^{2} + 32 = 12( {x}^{2} + 4) \\ \Leftrightarrow {a}^{2} + 32 = 12a \\ \Leftrightarrow {a}^{2} - 12a + 32 = 0 \\ \Rightarrow Coefficients:1, \: -12. \: Constant:a
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3 years ago
The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0
3 years ago
I used the pythagorean theorem.<br><br> Need a second opinion
uysha [10]

Answer:

A.

Step-by-step explanation:

EF^2=18^2-12^2

EF^2=324-144

EF^2=180

EF=root 180

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3 years ago
Reverse percentage problem
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2 years ago
Jacqueline is checking her bicycle’s wheel. The wheel has a radius of 20 cm, and its center is 51 cm above the ground. Jacquelin
Alex777 [14]

Answer:

h = 36.9 cm

Step-by-step explanation:

The function given to us is:

h(t) = 51 + 20 sin(225t)

Where h(t) is the function of the height in centimeters while t represents the time in seconds.

We have to find the height h(t) when the time is equal to 19 seconds.

Substitute t=19 into the given function

h(19) = 51 + 20 sin(225(19))

h(19) = 51 + 20 sin(4275)

h(19) = 51 + 20 (-0.7071)

h(19) = 51 + (-14,1421)

h(19) = 36.8579 cm

Rounding off to nearest 10th

h = 36.9 cm

6 0
3 years ago
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