3(8-4x)<6(x-5)
24 - 12x < 6x - 30
18x > 54
x > 3
answer is B. x > 3
<em>Sure hope this helps you! :D</em>
44
Step-by-step explanation:
let boys be x and girls be y
x/y=5/6
x=5y/6....(1)
if 6 boys join the club that will be x+6
Therefore:
(x+6)/y=13/12
13y=12x+72
13y-12x=72
Recall x=5y/6
Therefore:
13y-12(5y/6)=72
13y-(2*5y)=72
13y-10y=72
3y=72
y=24 people
Therefore:
x=(5*24)/6
x=20 people
Therefore people in the club before are 20+24=44
Answer: huh?? Need more info.
Step-by-step explanation:
For this problem, the most accurate is to use combinations
Because the order in which it was selected in the components does not matter to us, we use combinations
Then the combinations are 
n represents the amount of things you can choose and choose r from them
You need the probability that the 3 selected components at least one are defective.
That is the same as:
(1 - probability that no component of the selection is defective).
The probability that none of the 3 selected components are defective is:

Where
is the number of ways to select 3 non-defective components from 117 non-defective components and
is the number of ways to select 3 components from 120.


So:

Finally, the probability that at least one of the selected components is defective is:

P = 7.4%
Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)