Answer:
50%
Explanation:
According to the given information, the allele for the red-green colorblindness is inherited in an X linked recessive manner. Let's assume that the allele X^c is responsible for red-green colorblindness. The woman is normal but had a colorblind father (X^cY). Fathers give their X chromosomes to the daughters while their Y chromosome is transmitted to their sons. The sons get their X chromosomes from the mother.
The colorblind father has transmitted the X-linked allele for the red-green colorblindness to his daughter. Therefore, the genotype of the woman is X^cX. The woman would produce two types of eggs: 50 % with X^C and 50% with X. Therefore, 50% of sons of this woman would get X linked allele for the red-green colorblindness and would be affected by the disorder while the rest 50% of her sons will be normal.
A sperm and an egg cell are each gametes. They fuse to become a zygote cell which develops into a fetus
Answer:
<em>This question includes the following options:</em>
<em>A.</em><em>1 - </em><em>B.</em><em>3 - </em><em>C.</em><em>6 - </em><em>D</em><em>.8 -</em><em> E.</em><em> 12</em>
PCR which stands for <em>"Polymerase Chain Reaction"</em> is a molecular biology procedure to quickly multiply a small sample of DNA into millions or billions of DNA copies for studying purposes.
<em>"Unlinked"</em> signifies that the markers are present in 6 various chromosomes, but to amplify those markers we would need <em>(</em><em>12</em><em>)</em> unique primer sequences, due to it is required to have the reverse and forward primers for every marker; thereby the answer is <em>(</em><em>E.</em><em>)</em>
