Answer:14
Step-by-step explanation:
Answer:
68% Confidence interval = [4.5752, 4.5848]
95% Confidence interval = [4.5688, 4.5918]
Step-by-step explanation:
Sample mean (X) = 4.580
Sample Standard Deviation (S) = 0.01065
Sample size (n) = 6
for alpha/2 0.84 = 1.1037
for alpha/2 0.975 = 2.5706
68% Confidence interval = ![[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)]\frac{S}{\sqrt{n}}]](https://tex.z-dn.net/?f=%5Bx-T_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%2C%20x%2BT_%7B%285%29%5D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%5D)
= [4.5752, 4.5848]
95% Confidence interval = ![[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)}\frac{S}{\sqrt{n}}]](https://tex.z-dn.net/?f=%5Bx-T_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%2C%20x%2BT_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%5D)
= [4.5688, 4.5918]
Answer:
0.362
Step-by-step explanation:
When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:
- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.
- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14
- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7
- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.
Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability
P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362
Answer:
You use the formula (y to the second power minus y to the first power minus the same formula with the two different points
Step-by-step explanation:
Do you know that multiplicity means the number of times any factor appears in the factored result? Just checking. For example The graph of y = x^2 - 2x + 1 has a multiplicity of 2. they are y = (x - 1) * ( x - 1)
y = x^2 - 3x - 4 has 2 factors.
y = (x - 4)(x + 1) each of the factors has a multiplicity of 1.
So the answer to your question is there are 5 real zeros and 2 complex zeros.
