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Dmitrij [34]
3 years ago
10

How can you find the measurement of an missing

Mathematics
1 answer:
Harman [31]3 years ago
8 0
Wild guess?



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The equation of a line is 
nadezda [96]
The answer to the question

6 0
3 years ago
Charlie, a science teacher, worked 10 months out of the year. What percent of the year did he work?
Lina20 [59]

Answer:

10/12x100%= 83.3%

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can anyone solve this? If so tell me and make sure u know what ur doing please
raketka [301]

Answer:

-2

Step-by-step explanation:

To find the slope of a line, you need to find the \frac{rise}{run} between two points. I will be using the points (-3, 2) and (-1, -2).

\frac{rise}{run} = \frac{-2-2}{-1-(-3)}

     = \frac{-2-2}{-1+3}

     = \frac{-4}{2}

     = -2

6 0
3 years ago
Can you please help!! I need it ASAP! ;(
Ivahew [28]

Answer:

-8 just add them together

8 0
3 years ago
Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x
Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

f(x) = (x - (7 + i)) (x - (5 - i))

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48

5 0
2 years ago
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