The linear equations are y - 25 = 0.89(x - 20) and y = 0.89x + 7.2
<h3>The slope of the line</h3>
The complete question is added as an attachment
The two points from the graph are (20, 25) and (38, 41)
The slope of the line is calculated using
m = (y2 - y1)/(x2 - x1)
Substitute the known values in the above equation
m = (41 - 25)/(38 - 20)
Evaluate
m =0.89
<h3>The linear equation in point slope form</h3>
This is calculated as:
y - y1 = m(x - x1)
Substitute the known values in the above equation
y - 25 = 0.89 * (x - 20)
Evaluate
y - 25 = 0.89(x - 20)
<h3>The linear equation in slope-intercept form</h3>
We have:
y - 25 = 0.89(x - 20)
Expand
y - 25 = 0.89x - 17.8
Add 25 to both sides
y = 0.89x + 7.2
Hence, the linear equations are y - 25 = 0.89(x - 20) and y = 0.89x + 7.2
Read more about linear equations at:
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You can do this by completing the square
x^2 - 14x + y^2 + 8 = 16
(x - 7)^2 - 49 + (y + 4)^2 - 16 = 16
(x - 7)^2 + (y + 4)^2 = 16 + 16 + 49 = 81
so the center is at (7 , -4) and radius = sqrt81 = 9
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The correct question is
<span>In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π/3 radians. What is the length of the arc?
we know that
in a circle
</span>2π radians -----------------> lenght of (2*π*r)
2π/3 radians--------------> X
X=[(2π/3)*(2π*r)]/[2π]=(2π/3)*r
the lenght of the arc=(2π/3)*3=2π ft
the answer is 2π ft