1 answer:
Pile Y has the greater mean number of pages per book because it is 5 books less than pile W.
<h3>How to calculate greater mean number of pages?</h3>From the complete information, we can deduce that the number of each pile of book is given as follows:
<u>For pile W;</u>
Red books = 10 × 5 = 50 red books.
Blue books = 5 × 5 = 25 blue books.
Therefore, total books in pile W = 50 + 25 = 75 books.
Mathematically, the mean for each pile can be calculated by using the following formula:
Mean = [F(x)]/n
Mean = 75/10
Mean = 7.5.
<u>For pile Y;</u>
Red books = 10 × 5 = 50 red books.
Mean = [F(x)]/n
Mean = 50/5
Mean = 10.
In conclusion, pile Y has the greater mean number of pages per book because it is 5 books less than pile W.
Read more on mean here: brainly.com/question/9550536
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Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.
<h3>What is the hypergeometric distribution formula?</h3>The formula is:
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- There are 12 bulbs, hence N = 12.
- 3 are defective, hence k = 3.
The third defective bulb is the fifth bulb if:
- Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
- The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.
Hence:
0.2182 x 1/8 = 0.0273.
0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394