It's the reflexive property because it's just relating it to itself (def. of reflexive)
As we all know: A=A, B=B, mx=mx, nothing changes.
So the answer is D
1/2-1/4
(1/2x2)-1/4
2/4-1/4
2-1
1
1/4
Answer:
Step-by-step explanation:2 and 4
First, let me do the Mathematical part of that, and then I shall explain the theory behind it.
Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.
Multiply 513 with 6 first.
513
x46
--------------------------
18 (as 6*3 = 18)
60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)
Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.
Check: If we check the multiplication result by using the calculator, we would get the same result (23598).
Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.
Answer: C
Step-by-step explanation:A proportional relationship is a relationship which crosses through the origin (0,0) and which has a proportional constant. We can determine this either by finding (0,0) where x=0 and y=0 in the table or by dividing y/x. None of the tables contain (0,0) so we will divide y by x. We are looking for a table which when each y is divided by its x we have the same constant appearing.
These fractions are not equal. This is not proportional.
x 2 3 4 5
y 7 9 11 13
These fractions are not equal. This is not proportional.
x 3 7.5 15 20
y 1 2.5 4 6
These fractions are not equal. This is not proportional.
x 3 6 8 10
y 12 15 18 20 HOPE IT HELPS:P
<h2>SO C</h2>
