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Sergio [31]
3 years ago
5

PLEASE HELP ME ((UNIT RATES)) 20 points again, brainliest will be given.

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

I think the answer is A sorry if it's wrong

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Debora [2.8K]
The answer would be a ikk
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3 years ago
A cylindrical tank has a height of 10 feet and a radius of 4 feet. Carla fills the tank with water at a rate of 8 cubic feet per
Vikki [24]
Area = 10(pi)(16) = 160pi cubic feet
160pi = 502.56
502.56/8 = 63 minutes
5 0
3 years ago
Bruce owns a business that produces widgets. He must bring in more in revenue than he pays out in costs in order to make a profi
11111nata11111 [884]

Answer:

Bruce needs to sell 267 widgets each month to make a profit.

Step-by-step explanation:

From the information given, you can write that the cost of the monthly rent plus the cost  in labor and materials to make each widget for the number of widgets is equal to the amount of sales:

10x +4000 = 25x

Now, you can solve for x:

4000 =25x-10x

4000=15x

x= 266.67→267

According to this, the answer is that Bruce needs to sell 267 widgets each month to make a profit.

3 0
4 years ago
Write 6 × 10 -7 in decimal notation.<br><br> 0.0000006<br> 0.00006<br> 600,000<br> 6,000,000
Lina20 [59]
I’m pretty sure the answer is B
3 0
3 years ago
Divide 9x ^ 3 + 18x ^ 2 - 13x + 5 by 3x - 1 using division and write the division in the form P = DQ + R
lana66690 [7]

Answer:

\frac{9x^3\:+\:18x\:^2\:-\:13x\:+\:5}{3x-1}=9x^3+18x^2-13x+5

Step-by-step explanation:

DIVISION ALGORITHM: If p(x) and d(x)\neq 0  are polynomials, and the degree of d(x) is less than or equal to the degree of f(x),  then there exist unique polynomials q(x) and r(x), so that

                                               \frac{p(x)}{d(x)} =q(x)+\frac{r(x)}{d(x)}

and so that the degree of r(x)  is less than the degree of d(x).

To find \frac{9 x^{3} + 18 x^{2} - 13 x + 5}{3 x - 1} you must:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}9x^3+18x^2-13x+5\\\mathrm{and\:the\:divisor\:}3x-1\mathrm{\::\:}\frac{9x^3}{3x}=3x^2

\mathrm{Quotient}=3x^2

\mathrm{Multiply\:}3x-1\mathrm{\:by\:}3x^2:\:9x^3-3x^2\\\mathrm{Subtract\:}9x^3-3x^2\mathrm{\:from\:}9x^3+18x^2-13x+5\mathrm{\:to\:get\:new\:remainder}\\

\mathrm{Remainder}=21x^2-13x+5

Therefore,

\frac{9x^3+18x^2-13x+5}{3x-1}=3x^2+\frac{21x^2-13x+5}{3x-1}

\mathrm{Divide}\:\frac{21x^2-13x+5}{3x-1}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}21x^2-13x+54\\\mathrm{and\:the\:divisor\:}3x-1\mathrm{\::\:}\frac{21x^2}{3x}=7x\\\\\mathrm{Quotient}=7x

\mathrm{Multiply\:}3x-1\mathrm{\:by\:}7x:\:21x^2-7x\\\mathrm{Subtract\:}21x^2-7x\mathrm{\:from\:}21x^2-13x+5\mathrm{\:to\:get\:new\:remainder}\\\\\mathrm{Remainder}=-6x+5

Therefore,

\frac{21x^2-13x+5}{3x-1}=7x+\frac{-6x+5}{3x-1}\\\\\frac{9x^3+18x^2-13x+5}{3x-1}=3x^2+7x+\frac{-6x+5}{3x-1}

\mathrm{Divide}\:\frac{-6x+5}{3x-1}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x+5\\\mathrm{and\:the\:divisor\:}3x-1\mathrm{\::\:}\frac{-6x}{3x}=-2\\\\\mathrm{Quotient}=-2

\mathrm{Multiply\:}3x-1\mathrm{\:by\:}-2:\:-6x+2\\\mathrm{Subtract\:}-6x+2\mathrm{\:from\:}-6x+5\mathrm{\:to\:get\:new\:remainder}\\\\\mathrm{Remainder}=3

Therefore,

\frac{-6x+5}{3x-1}=-2+\frac{3}{3x-1}\\\\\frac{9x^3+18x^2-13x+5}{3x-1}=3x^2+7x-2+\frac{3}{3x-1}

6 0
4 years ago
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