What are some problems that can occur when using overrides? Check all that apply.
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Answer:
B.
Step-by-step explanation:
hope it helps :)
Answer: 
Step-by-step explanation:
Given : The height of the rectangle = 
The width of the rectangle = 
Formula : Area = height x width
Therefore , the area of triangle in terms of polynomial will be :
![6k^3\times( 2k^2+4k+5)\\\\= 6k^3(2k^2)+6k^3(4k)+6k^3(5)\ \ [\text{Using Distributive property}]\\\\=12k^{3+2}+24k^{3+1}+30k^3\ \ [\text{Using exponents rule}:\ a^n\times a^m=a^{n+m}]\\\\=12k^5+24k^4+30k^3](https://tex.z-dn.net/?f=6k%5E3%5Ctimes%28%202k%5E2%2B4k%2B5%29%5C%5C%5C%5C%3D%206k%5E3%282k%5E2%29%2B6k%5E3%284k%29%2B6k%5E3%285%29%5C%20%5C%20%5B%5Ctext%7BUsing%20Distributive%20property%7D%5D%5C%5C%5C%5C%3D12k%5E%7B3%2B2%7D%2B24k%5E%7B3%2B1%7D%2B30k%5E3%5C%20%5C%20%5B%5Ctext%7BUsing%20exponents%20rule%7D%3A%5C%20a%5En%5Ctimes%20a%5Em%3Da%5E%7Bn%2Bm%7D%5D%5C%5C%5C%5C%3D12k%5E5%2B24k%5E4%2B30k%5E3)
Hence, the area of the entire rectangle =
I got 29.2 (I also rounded it to the nearest tenth for u)
Answer:

Step-by-step explanation:
If the extreme ends of a line segment AC are A
and C
.
If a point B(x, y) divides the segment in the ratio of m : n
Then the coordinates of the point B are,
x = 
y = 
If the ends of AC are A(-2, 5) and C(2, -5) and a point B divides it in the ratio of m : n = 5 : 1
Therefore, coordinates of this point will be,
x = 
= 
= 
= 
y = 
= 
= 
= 
Therefore, coordinates of the point B are
.