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vaieri [72.5K]
3 years ago
6

20 points! If a translation maps ∠D onto ∠B, which of the following statements is true?

Mathematics
2 answers:
Fittoniya [83]3 years ago
8 0

Answer:

<E = <A

Step-by-step explanation:

If <D maps onto <B the triangles are similar

CDE is similar to CBA

That means The angles are congruent and the sides are proportional

<C = <C

<D = <B

<E = <A

The sides are not congruent but proportional (In a ratio)

CD    CE        DE

----- = ------ = -----

CB     CA      BA

madam [21]3 years ago
5 0
C
The two triangles are similar — that is, the three angles in triangle EDC correspond to those in ABC
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Please help.
ryzh [129]

Answer:

E and D

Step-by-step explanation:

3 0
3 years ago
Suppose that f: R --&gt; R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su
Pachacha [2.7K]
<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

f(x+y)=f(x)+f(y)------(1)  ∀  x,y ∈ R

Now, let us assume f(1)=k

Also,

  • f(0)=0

(  Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0  )

Also,

  • f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1)         ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

  • Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}

Also,

  • when x∈ Q

i.e.  x=\dfrac{p}{q}

Then,

f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

\to x )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence a_n such that:

a_n\ belongs\ to\ Q

and

a_n\to \alpha

f(a_n)=ka_n

( since a_n belongs to Q )

Let f is continuous at x=α

This means that:

f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha

This means that:

f(\alpha)=k\alpha

                       This means that:

                    f(x)=kx for every x∈ R

4 0
3 years ago
-Ready Understand On Earth Day, 40 people volunteert are high-school students. The coordi in high school. ). Write a fraction to
Elden [556K]

Answer:

1/40

Step-by-step explanation:

4 0
3 years ago
To convert a temperature measured in degrees Fahrenheit to degrees Celsius, there is a formula
e-lub [12.9K]

Answer:

113`F= 46.11° Celsius

Step-by-step explanation:

(Celsius°C × 9/5) + 32 = Fahrenheit

(Celsius°C × 9/5) + 32 = 113

(Celsius°C × 9/5) = 113 - 32

(Celsius°C × 9/5) = 83

Celsius = 5(83)/9

Celsius  = 46.11° Celsius

6 0
2 years ago
Read 2 more answers
Evaluate the expression<br><br> (3+2) x (5-1+2) x 4
Elza [17]
PEMDAS

(3+2)=5
(5-1+2)=6
6*5*4=120
3 0
3 years ago
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