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photoshop1234 [79]
2 years ago
12

Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthes

is.) and has a slope of StartFraction 3 Over 4 EndFraction.?
Mathematics
1 answer:
Marta_Voda [28]2 years ago
5 0

Step-by-step explanation:

hope you can understand

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9. Abby walked 3 km west. Then she walked
masya89 [10]

Answer:

2km

Step-by-step explanation:

- Abby walked 3 km west: Abby is 3km west from her starting point.

- Then she walked  twice as far going east: she walks 6km east so she's 3 km east from her starting point

- She continued east  for another kilometre: She's is 4 km east from her starting point

- Stopping 2 km east  of Lauren's home: She's currently 2 km east from Lauren's home and 4km east from her starting point. Therefore, Abby's starting point is 4km - 2km = 2km west from Lauren's home

8 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–3, –2) and (7, –6). Round to the nearest tenth if necessa
jarptica [38.1K]

The standard form for the equation of a circle is :

 (x−h)^2+(y−k)^2=r2 ----------- EQ(1)

 where handk are the x and y coordinates of the center of the circle and r is the radius.

 The center of the circle is the midpoint of the diameter.

 So the midpoint of the diameter with endpoints at (−3,-2)and(7,-6) is :

 ((−3+7)/2,(-2+(-6))/2)=(2,-4)

 So the point (2,-4) is the center of the circle.

 Now, use the distance formula to find the radius of the circle:

 r^2=(−3−(2))^2+(-2-(-4))^2=25+4=29

 ⇒r=√29

 Subtituting h=2, k=-4 and r=√29 into EQ(1) gives :

 (x-2)^2+(y+4)^2=29

4 0
3 years ago
A biologist is developing two new strains of bacteria. Each sample of Type 1 bacteria produces four new viable bacteria, and eac
gayaneshka [121]

The cost can be optimized by using a Linear Programming given the  linear constraint system

  • To minimize the cost, the biologist should use <u>60 samples of Type I</u> bacteria and <u>0 samples of Type II</u> bacteria

Reason:

Let <em>X</em> represent Type 1 bacteria, and let <em>Y</em>, represent Type II bacteria, we have;

The constraints are;

4·X + 3·Y ≥ 240

20 ≤ X ≤ 60

Y ≤ 70

P = 5·X + 7·Y

Solving the inequality gives;

4·X + 3·Y ≥ 240

  • Y \geq 80 - \dfrac{4}{3} \cdot X (Equation for the inequality graphs)

The boundary of the feasible region are;

(20, 70)

(20, 53.\overline 3)

(60, 0)

(60, 70)

The cost are ;

\begin{array}{|c|c|c|}X&Y&P= 5\times X + 7 \times Y\\20&70&590\\20&53.\overline 3&473.\overline 3\\60&0&300\\60&70&790\end{array}\right]

  • Therefore, the minimum cost of $300 is obtained by using <u>60 samples of Type I</u> and <u>0 samples of Type II</u>

Learn more here:

brainly.com/question/17646656

6 0
3 years ago
I need help with this ASAP
disa [49]

Answer:

The 2nd answer: y = 1/2x

Step-by-step explanation:

2 x 1/2= 1 and if you do 1/2 times x you'll see it works. Hope this helps!

4 0
3 years ago
Need answer for test important
Natalija [7]

Step-by-step explanation:

where does it cross the y-axis ?

at y = -8

8 0
3 years ago
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