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Anna11 [10]
3 years ago
11

What is 916,000 in scientific notation?

Mathematics
2 answers:
madam [21]3 years ago
5 0
916,000 = 9.16 x 10^-5

Hope This Helps You!
lubasha [3.4K]3 years ago
3 0
I believe it would be 9.16 x 10^5.

I hope this answer helps you.
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Quick question
zaharov [31]

Answer:

False

Step-by-step explanation:

Let us evaluate the problem using the proper order of operation:

           4x − 2(5x − 1)

To solve this problem, we use the order of operation called PEMDAS;

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

Now, since operations inside the parentheses are of the utmost priority, let us solve this;

             4x − 2(5x − 1)

            = 4x - 10x +2

            = -6x + 2  or 2 - 6x

We see that the solution give is false.

7 0
3 years ago
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Easyish PreCalculus; Find the exact values of the six trigonometric functions of the given angle. (you can use a calculator.) (D
Brut [27]

Answer:

there is no given angle here man

Step-by-step explanation:

5 0
3 years ago
Order from least to greatest 0.5, 1/5, 0.35, 12/25, 4/5
sdas [7]
First change them all into either fractions or decimals. Decimals are probably easier though. 1/5 = 0.2; 12/25 = 0.48; 4/5 = 0.8 
Order: 0.2, 0.35, 0.48, 0.5, 0.8
Then you change the decimals that you converted back into the fraction form
Answer: 1/5, 0.35, 12/25, 0.5, 4/5
5 0
3 years ago
What is y - 8 = -1/2 (x + 4) in standard form (8th grade math)
Natalija [7]
Y-8=-1/2x + (-2)
  +8               +8
y=-1/2x +6
I just used a 2 step equation for it. I first used Distributive Property. Then Subtracted 8 from each side
7 0
3 years ago
Two fair dice, one blue and one red, are tossed, and the up face on each die is recorded. Define the following events:
ZanzabumX [31]

Answer:

Step-by-step explanation:

Given that two fair dice, one blue and one red, are tossed, and the up face on each die is recorded.

a) P(E) = P(the difference of the numbers is 3 or more}

Favourable events are (1,4) (1,5)(1,6) (2,5) (2,6) (3,6) (4,1) (5,1) (5,2) (6,1) (6,2)(6,3)

P(E) = \frac{12}{36} =\frac{1}{3}

b)P(F)

Favourable events for F = (1,1) (2,2)...(6,6)

P(F) = \frac{6}{36} =\frac{1}{6}

c) P(EF)

There is no common element between E and F

P(EF) =0

4 0
3 years ago
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