Answer:
347
Step-by-step explanation:
i added them all
Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer
we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0
using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3
the answer is
the first odd integer x is 1
the second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5
First club
y= 40 + 10x y= 40 + 10(8) =120
Second club
y= 15x y= 15(8) =120
now plug a number of the answer choices in each equation until you get the same result for both
The answer is C
Answer:
3, 15, 14
Step-by-step explanation:
x + 5x + ( 5x -1) = 32
11x - 1 = 32
11x = 32 + 1
11x = 33
11x/11 = 33/11
x = 3
therefore
the first number is 3
the second is 5 × 3 = 15
the third number is 15 - 1 = 14