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Grace [21]
3 years ago
10

Moe painted the lid of a barrel. The circumference of the lid is 32 pi( pie) inches. Which measurement is closest to the area of

the lid in square inches?
Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Answer:

Area of lid = 804.35 square inches.

Step-by-step explanation:

Given the following data;

Circumference of lid = 32π inches

To find the area of the lid;

First of all, we would find the radius of the lid (circle).

Circumference of circle = 2πr

Substituting into the formula, we have;

32π = 2πr

Radius, r = 32π/2π

Radius, r = 16 inches.

Now, we can solve for the area of the circle using the formula;

Area of circle = πr²

Area of lid = 3.142*16²

Area of lid = 3.142 * 256

Area of lid = 804.35 square inches.

In terms of pie, area of lid = 256π square inches.

Therefore, the measurement which is closest to the area of the lid in square inches is 804.35 or 256π.

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n+3

Step-by-step explanation:

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Using the formula for area of a circle:

Area = pi x radius^2

Replace area with the given value:

39.62 = pi x radius^2

Divide both sides by pi

Radius^2 = 39.62/pi

Radius^2 = 12.62

Solve for radius by taking the square root of both sides

Radius = sqrt(12.62)

Radius = 3.55 cm

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A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2
Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find P(4.2

To find P(4.2, we need to use z score formula:

When x = 4.2, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1

When x = 5.1, we have:

z = \frac{x-\mu}{\sigma}

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Therefore, we have to find P(-1

Using the standard normal table, we have:

P(-1= P(z

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2 times the sum of 3 and 6z
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This is how you do it
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Step-by-step explanation:

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And since the maximum number of students in the school is given by the variable of Z, then Z is the number with which the domain closes.

The rank would be given by the set of [2, Z]

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