What is the value of x in the equation 2xt3y=36 When y= 6

dlinn [17]

Solutions

1) Add the whole numbers first ( 7 and 2 )

9+7/8+11/12

2) Find the Least Common Denominator (LCD) of

7 / 8,11 / 12

Start by Listing Multiples

List out all multiples of each denominator, and find the first common one.

8 : 8,16,24

12 : 12,24

Therefore, the LCD is 24

Method 2: By Prime Factors

List all prime factors of each denominator, and find the union of these primes.

8 : 2,2,2

12 : 2,2,3

Therefore, the LCD is 2×2×2×3=24

3) Make the denominators the same as the LCD

9+7×3 / 8×3+11×2 / 12×2

4) Simplify. Denominators are now the same

9+21 / 24+22 / 24

5) Join the denominators

9+21+22 / 24
6) Simplify

9+43 / 24

7) Convert 43 / 24 to mixed fraction

9+1 19 / 24

8) Simplify

10 19 / 24

4 0

4 years ago

If f(x) = |x – 2| then find f(-3).

MArishka [77]

Answer:

5

Step-by-step explanation:

f(x) = |x – 2|

f(3) = |-3 - 2| = |-5| = 5

8 0

3 years ago

The perimeter of a triangle is 93 ft. Side a of the triangle is twice as long as side b. Side c is 3 ft longer than side a. Find

Sunny_sXe [5.5K]

The length of side a is 36 feet and side b is 18 feet and side c is 39 feet

Solution:

Given that perimeter of triangle is 93 feet

The three sides of triangle are a, b, and c

Given that Side a of the triangle is twice as long as side b

side a = 2 times side b

a = 2b

$b = \frac{a}{2}$ ---- eqn 1

Given that Side c is 3 ft longer than side a

side c = 3 + side a

c = 3 + a ------ eqn 2

The perimeter of triangle is given as:

p = a + b + c

Where a, b, c are the length of sides of triangle

Substitute eqn 1 and eqn 2 in above formula

$p = a + \frac{a}{2} + 3 + a$

Given that perimeter = 93

$93 = a + \frac{a}{2} + 3 + a\\\\93 = \frac{2a + a + 6 + 2a}{2}\\\\93 \times 2 = 2a + a + 6 + 2a\\\\186 = 5a + 6\\\\5a = 186 - 6\\\\5a = 180\\\\a = 36$