Answer:
C. j=2 and h=4
Step-by-step explanation:
Step 1: Create a system of equations for your problem based off what we know.
- we should know that the equation to find the perimeter of something is
where <em>P</em> is the perimeter, <em>l </em> is the length, and <em> w </em> is the width.
- we know that the perimeter of Rectangle P is 20 inches and that the perimeter of Rectangle Q is 30
- we know the length and width of both rectangles
Using this information, lets set up our system.:
![\left \{ {{20=2(j+4)+2h} \atop {30=2(3h)+2(j+1)}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7B20%3D2%28j%2B4%29%2B2h%7D%20%5Catop%20%7B30%3D2%283h%29%2B2%28j%2B1%29%7D%7D%20%5Cright.)
Step 2: Using the top equation we're going to try to solve for one of the variables. I chose to solve for variable <em>j.</em>
![20=2(j+4)+2h](https://tex.z-dn.net/?f=20%3D2%28j%2B4%29%2B2h)
Start by distributing 2 into j + 4.
![20=2j+8+2h](https://tex.z-dn.net/?f=20%3D2j%2B8%2B2h)
Now subtract 8 from both sides of the equation.
![12=2j+2h](https://tex.z-dn.net/?f=12%3D2j%2B2h)
Now isolate variable j by subtracting 2h from both sides of the equation.
![12-2h=2j](https://tex.z-dn.net/?f=12-2h%3D2j)
Now condense the equation into simple terms by dividing both sides by its GCF 2 then reorder to get j on the left.
![j=6-h](https://tex.z-dn.net/?f=j%3D6-h)
Step 3: Now that we solved for variable j we can now substitute j into one of our equations from the original system. I chose to use the bottom equation and chose to distribute it before substituting.
![30=6h+2j+2](https://tex.z-dn.net/?f=30%3D6h%2B2j%2B2)
Subtract two from both sides to isolate the variables
![28=6h+2j](https://tex.z-dn.net/?f=28%3D6h%2B2j)
Now we can plug j into our equation
![28=6h+2(6-h)](https://tex.z-dn.net/?f=28%3D6h%2B2%286-h%29)
Step 4: Distribute 2 into 6-h
![28=6h+12-2h](https://tex.z-dn.net/?f=28%3D6h%2B12-2h)
Step 5: Combine like terms
![28=4h+12](https://tex.z-dn.net/?f=28%3D4h%2B12)
Step 6: Subtract 12 from both sides of the equation
![16=4h](https://tex.z-dn.net/?f=16%3D4h)
Step 7: Divide both sides by 4
![4=h](https://tex.z-dn.net/?f=4%3Dh)
Now that we know that h=4 we can plug 4 into one of our earlier equations. I used j=6-h
![j=6-4\\j=2](https://tex.z-dn.net/?f=j%3D6-4%5C%5Cj%3D2)
Plug answers into either one of the original equations to check answer