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Alisiya [41]
1 year ago
8

WILL GIVE BRAILIEST: 8th grade: equations and geometry

Mathematics
2 answers:
Aloiza [94]1 year ago
8 0
That’s should he right but also it could of been 54
USPshnik [31]1 year ago
7 0

Answer:

C. j=2 and h=4

Step-by-step explanation:

Step 1: Create a system of equations for your problem based off what we know.

- we should know that the equation to find the perimeter of something is

P= 2l+2w where <em>P</em> is the perimeter, <em>l </em> is the length, and <em> w </em> is the width.

- we know that the perimeter of Rectangle P is 20 inches and that the perimeter of Rectangle Q is 30

- we know the length and width of both rectangles

Using this information, lets set up our system.:

\left \{ {{20=2(j+4)+2h} \atop {30=2(3h)+2(j+1)}} \right.

Step 2: Using the top equation we're going to try to solve for one of the variables. I chose to solve for variable <em>j.</em>

20=2(j+4)+2h

Start by distributing 2 into j + 4.

20=2j+8+2h

Now subtract 8 from both sides of the equation.

12=2j+2h

Now isolate variable j by subtracting 2h from both sides of the equation.

12-2h=2j

Now condense the equation into simple terms by dividing both sides by its GCF 2 then reorder to get j on the left.

j=6-h

Step 3: Now that we solved for variable j we can now substitute j into one of our equations from the original system. I chose to use the bottom equation and chose to distribute it before substituting.

30=6h+2j+2

Subtract two from both sides to isolate the variables

28=6h+2j

Now we can plug j into our equation

28=6h+2(6-h)

Step 4: Distribute 2 into 6-h

28=6h+12-2h

Step 5: Combine like terms

28=4h+12

Step 6: Subtract 12 from both sides of the equation

16=4h

Step 7: Divide both sides by 4

4=h

Now that we know that h=4 we can plug 4 into one of our earlier equations. I used j=6-h

j=6-4\\j=2

Plug answers into either one of the original equations to check answer

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Step-by-step explanation:

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Step-by-step explanation:

Hey there!

Follow the steps to get answer.

  • Use one point formula and find 1st equation.
  • After that you find the slope of second equation.
  • Use the condition of perpendicular lines and find the slope of first equation.
  • Put slope value of equation in equation (i) and simplify them to get equation.

The equation of a line passing through point (2,3) is;

(y-3)= m1(x-2).......(i).

Another equation is;

y =  \frac{ - 1}{2} x +  \frac{2}{3}

2nd equation..

Now, From equation (ii)

We have;

Comparing equation (ii) with y = mx+c.

We get;

Slope = -1/2.

For perpendicular lines,

m1 \times m2 =  - 1

m1 \times  \frac{ - 1}{2}  =  - 1

Therefore the slope is 2.

Put value of slope (m1) in equation (i). We get;

(y - 3) = 2(x - 2)

Simplify them to get equation.

(y - 3) = 2x - 4

y = 2x - 1

Therefore the required equation is y = 2x-1.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
4. Find the distance between the two points. Round to the nearest tenth if necessary.
Archy [21]

Answer:

Distance = 7.8 units

Step-by-step explanation:

In coordinate geometry, the distance between the 2 points is given by

Distance = \sqrt{(x1-x2)^{2} + (y1-y2)^{2} }

where (x1,y1) and (x2,y2) are coordinates of the 2 points.

Above the 2 points given are, (-2,-1) and (3,5).

<em>x1 = -2 , y1 = -1 , x2 = 3, y2 = 5</em>

<em>Distance = \sqrt{((-2)-(3))^{2} + ((-1)-(5))^{2} }</em>

<em>Distance = \sqrt{61}</em>

<em>Distance = 7.8102 units</em>

To the nearest tenth, Distance = 7.8 units

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