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lutik1710 [3]
2 years ago
9

The coach recorded the scores of nine different basketball players in their last game. ● The median number of points scored by t

hese nine players was 13. ● The mean number of points scored by these nine players was 12. Part A: List 9 values that could represent this data set. Part B: A 10th basketball player on this team scored 12 points in the last game. If her score is added to this data set, how will the median and mean change? Explain your reasoning.
Mathematics
1 answer:
IRINA_888 [86]2 years ago
4 0

The values that could represent this data set include 5, 6, 9, 10, 12, 10, 4, 6, and 19.

<h3>How to calculate the mean?</h3>

It should be noted that a mean simply means the average of a set of numbers.

In this case, the values that could represent this data set include 5, 6, 9, 10, 12, 10, 4, 6, and 19. Therefore, the mean will be:

= (5 + 6 + 9 + 10 + 12 + 4 + 6 + 19)/9

= 81/9

= 9

When a 10th basketball player on this team scored 12 points in the last game, the new mean will be:

= (81 + 12)/10

= 93/10

= 9.3

Therefore, there's an increase in mean.

Learn more about mean on:

brainly.com/question/1136789

#SPJ1

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ExtremeBDS [4]

Answer:

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

Step-by-step explanation:

Sea el punto debajo del puente el punto de referencia y que ambas lanchas se desplazan a velocidad a continuación, las ecuaciones cinemáticas para cada embarcación son presentadas a continuación:

Bote a 7 metros por segundo

x_{A} = x_{o}+v_{A}\cdot t (Ec. 1)

Lancha a 10 metros por segundo

x_{B} = x_{o}+v_{B}\cdot (t-3\,s) (Ec. 2)

Donde:

x_{o} - Posición debajo del puente, medido en metros.

x_{A}, x_{B} - Posición final de cada embarcación, medido en metros.

v_{A}, v_{B} - Velocidad de cada embarcación, medida en metros por segundo.

t - Tiempo, medido en segundos.

Para determinar la posición en la que ambas embarcaciones se encuentran, se debe determinar el instante en que ocurre a partir de la siguiente condición: x_{A} = x_{B}

Igualando (Ec. 1) y (Ec. 2) se tiene que:

v_{A}\cdot t = v_{B}\cdot (t-3\,s)

Ahora despejamos el tiempo:

3\cdot v_{B} = (v_{B}-v_{A})\cdot t

t = \frac{3\cdot v_{B}}{v_{B}-v_{A}}

Si sabemos que v_{B} = 10\,\frac{m}{s} y v_{A} = 7\,\frac{m}{s}, entonces:

t = \frac{3\cdot \left(10\,\frac{m}{s} \right)}{10\,\frac{m}{s}-7\,\frac{m}{s}}

t = 10\,s

Ahora, la posición de encuentro es: (x_{o} = 0\,m, v_{A} = 7\,\frac{m}{s} y t = 10\,s)

x_{A} = 0\,m + \left(7\,\frac{m}{s} \right)\cdot (10\,s)

x_{A} = 70\,m

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

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