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Lady_Fox [76]
3 years ago
6

In 2005, the shabelle river in Somalia rose an estimated 5.25 inches every hour for 15 hours. The increase in water level is rep

resented by the function f(x)=5.25x, where x is the number of hours. Graph this function and give it's domain and range. Is the function discrete or continuous?

Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

The Given situation is In 2005, the shabelle river in Somalia rose an estimated 5.25 inches every hour for 15 hours.

Increase in water level is represented by the function,f(x)=5.25 x.

or replacing f(x) by y we get ,y= 5.25 x

This is equation of straight line passing through the origin.

As x is number of hours , so x> 0,(0,∞] Which is it's domain.

As x> 0, so Range is those values of y for which x is defined.

x= \frac{y}{5.25},So Range is y>0 i.e (0,∞}

As the function has no breaking point , that is when you plot the graph on coordinate axis there is no breaking point.So , it is everywhere continuous i. e for all values of x.





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agasfer [191]

Answer:

25

Step-by-step explanation:

remember that the pythagorean theorem is a²+b²=c²

so this equation would be:

7²+24²=c²

solve the exponents

49 + 576 = c²

combine like terms

625 = c²

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√625 = √c²

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3 0
2 years ago
Find the least common multiple of: 12x^3y^2 and 15x^2y^5
allochka39001 [22]

Answer: 60x^3y^5

Step-by-step explanation:

Least Common Multiple :The least positive number that is a multiple of two or more numbers.

To find : The least common multiple of: 12x^3y^2 and 15x^2y^5.

Since, 12x^3y^2=2\times2\times3\times x^3y^2

15x^2y^5=3\times5\times x^2y^5

The least common multiple of: 12x^3y^2 and 15x^2y^5. = 2\times2\times3\times5\times x^3y^5=60x^3y^5 [take highest power of x and y ]

Hence, the least common multiple of: 12x^3y^2 and 15x^2y^5. = 60x^3y^5

3 0
3 years ago
Amy's math notebook weighs 1/2 pound, her science notebook weighs 7/8 pound, and her history notebook weighs 3/4 pound. What are
QveST [7]
1/2 is equal to 50%, 3/4 is equal to 75%, and 7/8 is equal to 87.5 percent. Therefore, the order is 1/2, 3/4, and then 7/8.
4 0
3 years ago
Read 2 more answers
1.) Which domain restrictions apply to the rational expression? 14x-2x / x^2-7x
mezya [45]

Answer:

3. \displaystyle 1\frac{1}{3} = x

2<em>C.</em> \displaystyle III.

2<em>B.</em> \displaystyle I.

2<em>A.</em> \displaystyle II.

1. \displaystyle Set-Builder\:Notation: [x|7, 0 ≠ x] \\ Interval\:Notation: (-∞, 0) ∪ (0, 7) ∪ (7, ∞)

Step-by-step explanation:

3. <em>See</em><em> </em><em>above</em>.

2<em>C</em>. The keyword is ratio, which signifies division, so you would choose "III.".

2<em>B</em>. The keyword is percent, which signifies multiplication of a ratio by 100, so you would choose "I.".

2<em>A</em>. The keyword is total, which signifies addition, so you would choose "II.".

1. Base this off of the denominator. Knowing that the denominator CANNOT be zero, you will get this:

\displaystyle x^2 - 7x \\ x[x - 7] = 0; 7, 0 = x \\ \\ Set-Builder\:Notation: [x|7, 0 ≠ x] \\ Interval\:Notation: (-∞, 0) ∪ (0, 7) ∪ (7, ∞)

I am joyous to assist you anytime.

5 0
3 years ago
Anyone know the answer please teach me
Semenov [28]

Answer: Look at step by step

Step-by-step explanation:

(a) There are 119 stocks that increased in price out of 246 stocks so the probability of selecting a stock that is increased in price is 119/246 = 48.37%

(b) There are 112 stocks where it pays dividends so the probability so the probability of selecting a stock that pays dividends is 112/246 = 45.53%

(c) There are 49 stocks which satisfy the question so the probability is 49/246 = 19.92%

(e) There are 34 stocks which increase in price and pay dividends out of the 119 stocks that increase in price so the probability is 34/119 = 28.57%

(f) Using the same logic as (e), the probability is 85/134 = 63.43%

(g) From the requirements, we see that 49 stocks don't satisfy the requirements, so the probability is (246-49)/246 = 80.08%

7 0
1 year ago
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