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2 years ago

What is the approximate value of the function at x = 6?

Mathematics

1 answer:

Gelneren [198K]2 years ago

5 0

Answer:

about 3/4

Step-by-step explanation:

To tell what the y value of a certain x value will be is very simple if we have a graph--you can just look at the portion of the graph where x = 6. At that point, it appears to be 3/4 ish on the y-axis

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Nathan invested $80,000 in an account paying an interest rate of 6% compounded

bija089 [108]

Answer:

Number of year = 13 year and 6 month approx.

Step-by-step explanation:

Given:

Amount invested = $80,000

Rate of interest = 6% compounded continuously

Future value of investment = $175,600

Find:

Number of year

Computation:

Future value of investment = Amount invested[1 + Rate of interest]ⁿ

175,600 = 80,000[1+6%]ⁿ

175,600 = 80,000[1+0.06]ⁿ

175,600 = 80,000[1.06]ⁿ

Number of year = 13.492 year

Number of year = 13 year and 6 month approx.

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

Marina86 [1]

Area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

$$=\frac{1}{4} \pi r^2 - \frac{1}{2} bh$

$$=\frac{1}{4} \pi \times 12^2 - \frac{1}{2} \times 12 \times 12$

$$=36\pi -72$

$$=36(\pi -2)$ square cm.

Area of the shaded region $$=36(\pi -2)$ square cm

Using Pythagoras theorem,

$AC^2=AB^2+BC^2$

$AC^2=12^2+12^2$

$AC^2=288$

Taking square root on both sides of the equation, we get

$AC= 12\sqrt 2$ cm

Perimeter of the quadrant of a circle = $\frac{1}{4} \times 2\pi r$

$$=\frac{1}{4} \times 2 \times \pi \times 12$

$$=6 \pi$ cm

Perimeter of the shaded region = $6 \pi + 12\sqrt 2$ cm

$=6 (\pi + 2\sqrt 2)$ cm

Hence area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

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