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miv72 [106K]
2 years ago
14

Denisa is saving for a new bicycle. The bicycle cost $89. So far, Denisa has earned $54 babysitting. What percent of the total c

ost of the bicycle has denisa already earned? round your answer to the nearest whole percent if necessary
Mathematics
2 answers:
xz_007 [3.2K]2 years ago
5 0
$54/$89 means she has dared 60.6742% or you can round to 60.67%
Lisa [10]2 years ago
5 0
65% is the answer.
89-54=35
100-35=65%
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Babies born after 40 weeks gestation have a mean length of 52.2 centimeters (about 20.6 inches). Babies born one month early hav
Sveta_85 [38]

Answer:

a) Z = -2.88

b) Z = -0.96

c) 40 weeks gestation babies

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. Find the standardized score (z-score), relative to all U.S. births, for a baby with a birth length of 45 cm.

Here, we use \mu = 52.2, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 52.2}{2.5}

Z = -2.88

b. Find the standardized score of a birth length of 45 cm. for babies born one month early, using 47.4 as the mean.

Here, we use \mu = 47.4, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 47.4}{2.5}

Z = -0.96

c. For which group is a birth length of 45 cm more common?

For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

3 0
3 years ago
tyra has 12 2/3 cups of sugar. if r is the amount of sugar needed for one batch of cookies, the expression 12 2/3 ÷ r can be use
olga nikolaevna [1]

ANSWER

She can make 19 batches of oatmeal.

EXPLANATION

First we can change the mixed number into an improper fraction:

12\frac{2}{3}=12+\frac{2}{3}=\frac{12\cdot3}{3}+\frac{2}{3}=\frac{36}{3}+\frac{2}{3}=\frac{38}{3}

In this problem, r = 2/3. The division is:

12\frac{2}{3}\div r=\frac{38}{3}\div\frac{2}{3}

Using the KFC rule:

\frac{38}{3}\div\frac{2}{3}=\frac{38}{3}\times\frac{3}{2}

Solving we can see that the denominator of the first fraction can be simpliied with the numerator of the second fraction:

\frac{38}{3}\times\frac{3}{2}=\frac{38}{1}\times\frac{1}{2}=\frac{38}{2}=19

Tyra can make 19 batches of oatmeal with 12 2/3 cups of sugar.

6 0
1 year ago
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