P= 16 over 3 this is the straight forward answer
Explanation:
6(2x + 5) = 2(3x – 2)
[given]
6(2x) + 6(5) = 2(3x) + 2(-2)
12x + 30 = 6x – 4
[distributive property of equality; individually multiply each addend inside the parenthesis and simplify (distribute the terms) ]
12x + 30 = 6x – 4
–6x –6x
6x + 30 = -4
[subtraction property of equality; subtract both sides by 6x in order to keep the x term on the left side]
6x + 30 = -4
–30 –30
6x = -34
[subtraction property of equality; subtract both sides by 30 in order to keep the constant term on the right side]
6x = -34
÷6 ÷6
x = -34/6
[division property of equality; divide both sides by 6 to eliminate the coefficient of 6 in 6x in order to obtain the variable x]
x = -17/3
[GCF(greatest common factor); divide both sides by the greatest common factor until both numbers are prime (only divisible by 1 and itself]
U turn negative numbers from mixed numbers to improper fractions the same way u do with positive...u just temporarily disregard the negative sign.
Example :
- 2 2/3.....temporarily disregard the negative sign......take ur whole number (2) and multiply it by ur denominator (3) giving u 6, then add that to ur numerator (2) giving u 8....then put that number over the original denominator (3) giving u 8/3...and then put back ur negative sign...-8/3
Answer:
x= 29/11 or y= 25/11
Step-by-step explanation:
2x - y= 3 ...........equation 1
x + 5y= 14 ............equation 2
Make x the subject of the formula in equation 2
x= 14 - 5y ..............equation 3
Substitute x=14 - 5y in equation 1
2(14- 5y) - y=3
28 - 10y - y=3
Collect like terms
-10y - y=3 - 28
-11y= -25
divide both sides by coefficient of y
-11y/-11 = -25/-11
y= 25/11
Substitute y= 25/11 in equation 3
x=14 - 5(25/11)
x= 14 - 125/11
x= 29/11
Answer:
There were 26 students in his class and the teacher had 83 ml of the solution.
Step-by-step explanation:
Mr. Kohl has a "x" amount of solution, if he divides it by the number of students "n" he'll give each student 3 milliliters and have a left over of 5 milliliters. If the amount of solution Mr. Kohl had was "x + 21" then he'd be able to give each student 4 milliliters of the solution. From these informations we have:
x = 3*n + 5
(x + 21)/n = 4
x + 21 = 4*n
x = 4*n - 21
Now that we have two equations and two variables we can solve the system of equations, as seen bellow:
3*n + 5 = 4*n - 21
3*n - 4*n = -21 - 5
-n = -26
n = 26
x = 4*26 - 21 = 83 ml
There were 26 students in his class and the teacher had 83 ml of the solution.
