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Anastaziya [24]
2 years ago
13

Complete the following table using the equation: y = -2x²

Mathematics
1 answer:
quester [9]2 years ago
4 0

The parabola is a downward parabola which is passing through origin and leading coefficient of the negative 2.

<h3>What is the parabola?</h3>

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

The equation of a quadratic function, of vertex (h, k), is given by:

y = a(x – h)² + k

where a is the leading coefficient.

The equation of the parabola will be

y = -x²

The given parabola is a downward parabola which is passing through origin and leading coefficient of the negative 2.

The graph of the function is given below.

More about the parabola link is given below.

brainly.com/question/8495504

#SPJ1

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If sin square theta = 0.75, then cos =
sergeinik [125]

Answer:

\cos\theta=\pm0.5

Step-by-step explanation:

Given:

\sin^2\theta=0.75

To find \cos\theta

Using trigonometric relations for sums and differences of squares of the ratios.

We know:

\sin^2\theta+\cos^2\theta =1

Plugging in  \sin^2\theta=0.75 in the above relation.

0.75+\cos^2\theta =1

Subtracting both sides by 0.75.

0.75+\cos^2\theta-0.75 =1-0.75

\cos^2\theta =0.25

Taking square root both sides.

\sqrt{\cos^2\theta} =\sqrt{0.25}

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6 0
3 years ago
One fourth the sum of x and ten is identical to x minus 4."
Lynna [10]

Answer and Step-by-step explanation:

We are given the word format of an equation.

Let's right it out in numerical form.

\frac{1}{4} (x + 10) = x - 4

The first part says One fourth the sum of x and 10

The sum of x and 10 would be shown as x + 10, and one fourth of that means that \frac{1}{4} is multiplying (x + 10).

In this case, identical would mean equal to.

So, \frac{1}{4}(x + 10) would be = to something.

It says that it is identical to x minus 4 (x - 4).

\frac{1}{4} (x + 10) = x - 4<u> is the equation.</u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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