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likoan [24]
3 years ago
6

After the movie premiere 99 out of 130 people surveyed said they liked the movie. What is the experimental probability that the

next person suveyed will say he or she liked the movie?
Mathematics
1 answer:
Margaret [11]3 years ago
6 0
Out of the 130 people surveyed, 99 people said they liked the movie. So to figure out the probability that the next person likes the movie, you divide 99 from 130. 
The answer is approximately 76%.
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A recent study of 200 nurses found that of 125 female nurses 56 held bachelor's degrees; of the males 34 held bachelor's. If a n
bonufazy [111]
Need to develop a contingency table (often used for calculating probabilities when the focus is on conditional probability).

The nurse is either M or F.
The nurse either has a BS degree or does not.

Since there are 125 female nurses, and 56 of those held bachelors degrees, that leaves (125-56), or 69, who did not hold bachelors degrees.  Complete this table.  I found that there are 75 male nurses and 125 female nurses.  Note that 75 and 125 add up to 200 (which is the given number of nurses).
5 0
3 years ago
In the construction of a segment congruent to a given segment shown, what is CD?
pogonyaev

If segments AB and CD are congruent, then they have equal lengths:

5x-2=2x+7.

Solve this equation.

1. Separate terms with x and without x in different sides:

5x-2x=7+2,

3x=9.

2. Divide by 3:

x=3.

Then CD=2x+7=2·3+7=6+7=13.

Answer: correct choice is B.

4 0
3 years ago
Pls help i will mark brainliest
aksik [14]

Answer:

the answer is the first one I think but I'm pretty sure

6 0
3 years ago
Choice A: 3 nights and one meal for $ 250
Simora [160]
Let x be the price for each night and y be the price for each meal. Then, express the statements into mathematical equations:

Choice A: 3x + y = 250
Choice B: 3x + 6y = 330

Subtract both equations, the difference would be -5y = -80

-5y = -80
y = -80/-5
y = $16 per meal

3x + y = 250
3x + 16 = 250
3x = 250 - 16
3x = 234
x = 234/3
x = $78 per night

The answer is D.
8 0
3 years ago
Last year, a comprehensive report stated that 28% of businesses in the northeast of Ohio were considered highly profitable. This
Alik [6]

Answer:

z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575  

p_v =2*P(z>1.575)=0.115  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

Step-by-step explanation:

Data given and notation

n=50 represent the random sample taken

X=19 represent the businesses were highly profitable

\hat p=\frac{19}{50}=0.38 estimated proportion of businesses were highly profitable

p_o=0.28 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of businesses were highly profitable is different from 0.28 or no, the system of hypothesis is.:  

Null hypothesis:p=0.28  

Alternative hypothesis:p \neq 0.28  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>1.575)=0.115  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

4 0
4 years ago
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