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Aleonysh [2.5K]
3 years ago
10

I really need help please ​

Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer: one solution at ( -1, 2 )

Step-by-step explanation:

-x + 2y =5

x + y = 1

You cross out the x’s then add 2y + y which will give you 3y. Add the 5 and 1 and you’ll get 6.

3y = 6

Divide 3 to both sides

y = 2

To get x you’ll use the first equation.

-x + 2y = 5

Replace the y with 2

-x + 2(2) = 5

-x + 4 = 5

Move the 4 to the other side, but you’ll need to flip it to negative. So 5 - 4.

-x = 1

Divide both sides by -1

x = -1

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lesantik [10]

Answer:

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Step-by-step explanation:

\sqrt[4]{ {x}^{2} + 2x }  =  \sqrt[4]{35}  \\ {({x}^{2} + 2x) }^{ \frac{1}{4} }  =  {(35)}^{ \frac{1}{4} }  \\ {x}^{ \frac{1}{2} } + {2x}^{ \frac{1}{4} }   =  {35}^{ \frac{1}{4} }  \\   {x}^{2}  + 2x = 35 \\  {x}^{2}  + 2x  -  35 = 0 \\ (x - 5)(x + 7) = 0 \\ x = 5  \: or \:  - 7

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4 0
1 year ago
Can you guys help me plz
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Answer:

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