Answer:
Follows are the solution to this question:
Step-by-step explanation:
is invertible lines transformation
T is invertiable linear transformation means that is
and
Let
so,
![s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \ \forall \ \ v \ \ \varepsilon \ \ 1 R^n](https://tex.z-dn.net/?f=s%5BT%28u%29%5D%3Dv%5BT%28u%29%5D%5C%5C%5C%5Cs%28v%29%3Dv%28v%29%20%5C%20%5C%20%20%5Cforall%20%5C%20%5C%20v%20%5C%20%5C%20%5Cvarepsilon%20%5C%20%5C%201%20R%5En)
Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
-4/5 = -16/20, so the new expression is (-16/20)+(3/20)
then, -16 + 3 is -13, so the solution is -13/20
That will be 3,000 I guess I tried to help
2
3
-7
24
-25
-3
second row
-12
-2
-9
-38
10
-28