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Anni [7]
2 years ago
8

What is the diameter of the cylinder

Mathematics
2 answers:
vfiekz [6]2 years ago
5 0
  • Diameter of cylinder is <u>1</u><u>4</u><u> </u><u>units.</u>
<h3><u>Explamation </u><u>:</u></h3>

<em><u>Given </u></em><em><u>:</u></em><em><u>-</u></em>

  • Volume of cylinder = 245π cubic units
  • Height of cylinder = 5 units

<em><u>To </u></em><em><u>Find </u></em><em><u>:</u></em><em><u>-</u></em>

  • Diameter of cylinder?

<em><u>Solution </u></em><em><u>:</u></em><em><u>-</u></em>

<em>Firstly </em><em>lets </em><em>calculate </em><em>radius </em><em>of </em><em>cylinder </em><em>by </em><em>using </em><em>formula </em><em>of </em><em>volume </em><em>of </em><em>cylinder,</em><em> </em><em>as </em><em>we </em><em>know </em><em>that;</em>

  • Volume of cylinder = πr²h

<em>Putting </em><em>all </em><em>values </em><em>we </em><em>get;</em>

➸ 245π = π × r² × 5

<em>By </em><em>cutting </em><em>'π' </em><em>with </em><em>'π' </em><em>we </em><em>get;</em>

➸ 245 = r² × 5

➸ 245/5 = r²

➸ 49 = r²

➸ √(49) = r²

➸ √(<u>7</u><u> </u><u>×</u><u> </u><u>7</u><u>)</u> = r²

➸ 7 = r

➸ r = 7 units

  • <u>Hence,</u><u> </u><u>radius </u><u>of </u><u>cylinder </u><u>is </u><u>7</u><u> </u><u>units.</u>

<em>Now </em><em>lets </em><em>calculate </em><em>its </em><em>diameter,</em><em> </em><em>as </em><em>we </em><em>know </em><em>that;</em>

  • Diameter = Radius × 2

<em>Putting </em><em>all </em><em>values </em><em>we </em><em>get;</em>

➸ Diameter = 7 × 2

➸ Diameter = 14 units

  • <u>Hence,</u><u> </u><u>diameter </u><u>of </u><u>cylinder </u><u>is </u><u>1</u><u>4</u><u> </u><u>units.</u>

shusha [124]2 years ago
5 0

\\ \maltese \: \: \: \: \large{\underline{\underline{\pmb{\textsf{\color{blue}{Given \: :}}}}}}  \\ \\

  • Volume of Cylinder = 245 π cubic units.
  • Height of Cylinder = 5 units.

\\ \maltese \: \: \: \: \large{\underline{\underline{\pmb{\textsf{\color{green}{To \: Find \: :}}}}}} \\ \\

  • Diameter of Cylinder = ??

\\ \maltese \: \: \: \: \large{\underline{\underline{\pmb{\textsf{\color{aqua}{Solution \: :}}}}}}\\ \\

★ <u>Calculating the Radius of the Cylinder</u>;

\begin{gathered} \\ \maltese \: \: \: \: \large{\underline{\underline{\pmb{\textsf{\color{hotpink}{using \: formula \: :}}}}} } \\ \\ \end{gathered}

\red\bigstar { \underline{ \underline{\underline{\boxed{\color{brown}{\textbf{ \:Volume \:  =  \: πr²h   }}}}}} }\\ \\

Where ,

  • Volume = 245 π cubic units
  • π = pi
  • r = Radius
  • h = height = 5 units

\\  \sf \implies \: \:Volume \:  =  \: πr²h \\\\

\sf \implies \: \:275 \: \pi\:  =  \: π \:  \times  {r}^{2}  \:  \times  \: 5 \\  \\

\sf \implies \: \:275 \: \cancel{ \pi}\:  =  \: \cancel{ \pi} \:  \times  {r}^{2}  \:  \times  \: 5\\  \\

\sf \implies \: {r}^{2}\:  =  \:  \:   \frac{275}{5}  \\  \\

\sf \implies \: {r}^{2}\:  =  \:  \:    \cancel\frac{275}{5}  \\  \\

\sf \implies \: {r}^{2}\:  =  \:  \:    55  \\  \\

\sf \implies \: r\:  =  \:  \:    \sqrt{55  }\\  \\

\bf \implies \: r\:  =  \:  \:    5 \: units \: \\  \\

★ <u>Calculating the Diameter of the </u><u>Cylinder;</u>

\\ \sf \implies \: Diameter\:  =  \:  \:    Radius \: × \: 2 \\  \\

\\ \sf \implies \: Diameter\:  =  \:  \:    5 \: × \: 2 \\  \\

\\ \sf \implies \: Diameter\:  =  \:  \:    10 units .... \\  \\

henceforth, The Diameter of Cylinder is 10 units ..!!

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