Answer:
Question 1: y = 3/4x + 1/4.
Question 2: y = 6/5x + 7/5.
Step-by-step explanation:
Question 1: A line perpendicular to another line would have a slope that is the negative reciprocal of the other line. If the slope of the first line is -4/3, the slope of a line perpendicular to the first would have a slope of 3/4.
Since the line goes through (5, 4), we can just put the points into the equation, y = 3/4x + b.
4 = 3/4(5) + b
b + 15/4 = 4
b = 16/4 - 15/4
b = 1/4
So, the equation of the line is y = 3/4x + 1/4.
Question 2: 5x + 6y = -6
6y = -5x - 6
y = -5/6x - 1
As stated before, a line perpendicular to another will have a slope that is the negative reciprocal of the other. So, the slope of the other line is 6/5.
The line goes through (-2, -1), so we can put the points into the equation, y = 6/5x + b.
-1 = 6/5(-2) + b
b - 12/5 = -5/5
b = -5/5 + 12/5
b = 7/5
So, the equation of the line is y = 6/5x + 7/5.
Hope this helps!
