Mrs. Nygaard needs 12 hours to grade all of her students’ projects. She made a chart to show how much time she could spend gradi
1 answer:
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Answer:
Point-slope form of equation given as .
Slope-intercept form of equation is given as .
Step-by-step explanation:
In the question, it is given that the slope of a line is -2 and it passes from (-2,2).
It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.
To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.
Step 1 of 2
Passing point of the line is (-2,2).
Hence, and
Also, the slope of the line is -2.
Hence, m=-2
Substitute the above values in point-slope form of equation given by
Hence, point-slope form of equation given as y-2=-2(x+2).
Step 2 of 2
Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.
Hence, slope-intercept form of equation is given as y=-2x-2.
Answer:
Cos θ = -4/5
Tan θ = -3/4
Step-by-step explanation:
The question is as following:
Select the correct answer from each drop-down menu.
Angle θ lies in the second quadrant, and sin θ =3/5.
cos θ = -4/5, -3/5, 3/5, 4/5
tan θ = -4/3, -3/4, 3/4, 4/3
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Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.
If sin θ =3/5
∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.
And
Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.