Question

Helpppp! i need to find general form and standard form, pleaseee HELP MEEE!)!#*(_

Answer 1

The general form and the standard form of the graph equation are 13x - 8y = 17 and 13x - 8y - 17 = 0 respectively

How to determine the equations?

From the graph, we have the following points

(x,y) = (5,6) and (-3,-7)

Start by calculating the slope:

$m = \frac{y_2 - y_1}{x_2 -x_1}$

This gives

$m = \frac{-7 - 6}{-3 - 5}$

Evaluate the differences

$m = \frac{-13}{-8}$

Evaluate the quotient

$m = \frac{13}{8}$

The equation is then calculated as:

$y = m(x - x_1) + y_1$

This gives

$y = \frac{13}8(x - 5) + 6$

Multiply through by 8

8y = 13(x - 5) + 48

Open the bracket

8y = 13x - 65 + 48

Evaluate the like terms

8y = 13x - 17

Subtract 13x from both sides

-13x + 8y = -17

Multiply through by -1

13x - 8y = 17 ---- this represents the standard form

Subtract 17 from both sides

13x - 8y - 17 = 0 --- this represents the general form

Hence, the general form and the standard form of the graph equation are 13x - 8y = 17 and 13x - 8y - 17 = 0 respectively

Read more about linear equations at:

brainly.com/question/14323743

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