Ask question

Ask question

All categories

pishuonlain [190]

4 years ago

15

A dolphin is at -- 28 feet. It swims up and jumps out of the water to a height of 8 feet. Find the vertical distance the dolphin

travels. Justify your answer

1 answer:

Helga [31]4 years ago

6 0

Answer:

The vertical depth travelled by the dolphin = 36 feet

Step-by-step explanation:

The dolphin is a fish that can jump out of the water and therefore it is used in circus shows and exhibitions.

Initially the dolphin is at a depth of 28 feet deep inside the water surface.It comes to water surface and then jumps out of the water to a height of 8 feet.

The vertical distance travelled by the dolphin can be found by taking the difference of final height and initial depth.

Vertical depth = final height - initial depth

= 8 - (-28)

= 36 feet

The vertical depth travelled by the dolphin = 36 feet

You might be interested in

Graph f(x) = (1/3)^x+1<br>

e-lub [12.9K]

Answer:

The graph is attached below.

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(1/3\right)^x+1$

Exponentiation function have a horizontal Asymptotes.

<u />

<u>Finding the horizontal Asymptotes</u>

<u /> $\mathrm{Exponential\:function\:of\:the\:form}\:f\left(x\right)\:=c\cdot \:n^{ax+b}+k\:$ <u />

<u /> $\mathrm{has\:a\:horizontal\:asymptote}\:y=k\:$ <u />

<u /> $k=1$ <u />

<u /> $\mathrm{The\:horizontal\:asymptote\:is:}$ <u />

<u /> $y=1$ <u />

<u />

<u>Finding y-intercepts</u>

<u /> $y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0$ <u />

<u /> $y=\left(\frac{1}{3}\right)^0+1$ <u />

<u /> $\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0$ <u />

<u /> $\left(\frac{1}{3}\right)^0=1$ <u />

<u /> $y=1+1$ <u />

<u /> $\mathrm{Add\:the\:numbers:}\:1+1=2$ <u />

<u /> $y=2$ <u />

$\mathrm{Y\:Intercepts}:\:\left(0,\:2\right)$

The graph is attached below.

4 0

3 years ago

Elian and his friends paid a total of $7 for tickets to the school football game. While at the game, they bought 5 hot dogs at x

vagabundo [1.1K]

40 = 5+4+2=11

=40

HAVE A GOOD DAY

8 0

3 years ago

What is the equation of a parabola y(x) that has a vertex at point (− 1/3 , 0.3) and passes through point (− 2/15 , − 1/2 ).

Savatey [412]

bearing in mind that 0.3 = 3/10

$\bf ~\hfill \textit{parabola vertex form}~\hfill \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{we'll use this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-\frac{1}{3}}{ h},\stackrel{\frac{3}{10}}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y=a\left[ x-\left( -\cfrac{1}{3} \right) \right]^2+\cfrac{3}{10}\implies y=a\left( x+\cfrac{1}{3} \right)^2+\cfrac{3}{10}$

$\bf \textit{we also know a point } \begin{cases} x=-\frac{2}{15}\\\\ y=-\frac{1}{2} \end{cases}\implies -\cfrac{1}{2}=a\left( -\cfrac{2}{15}+\cfrac{1}{3} \right)^2+\cfrac{3}{10} \\\\\\ -\cfrac{1}{2}-\cfrac{3}{10}=a\left( \cfrac{1}{5} \right)^2\implies -\cfrac{4}{5}=a\left(\cfrac{1}{25} \right)\implies -\cfrac{4}{5}=\cfrac{a}{25}\implies \cfrac{-4\cdot 25}{5}=a \\\\\\ -4\cdot 5=a\implies \boxed{-20=a} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-20\left( x+\cfrac{1}{3} \right)^2+\cfrac{3}{10}~\hfill$

8 0

4 years ago

Someone plzzz helppp meee

sergij07 [2.7K]

Answer:

The answer is 40 degrees

5 0

3 years ago

Read 2 more answers

Devin paid $30 to be a member of the fox lake gym. When he takes the boxing class, it costs him $2. Jared is not a member of the

Paha777 [63]

For this case, the first thing we must do is define variables.

We have then:

x: number of classes:

y: total cost

For Devin we have the following equation:

$y = 2x + 30$

For Jared we have:

$y = 5x$

Then, by the time the cost of both is the same, we have:

$2x + 30 = 5x$

From here, we clear the value of x.

We have then:

$5x - 2x = 30$

$3x = 30$

$x = \frac{30}{3}$

$x = 10$

Answer:

it takes 10 classes for Devin's total cost to equal Jared's total cost

7 0

4 years ago

Read 2 more answers