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3 years ago

12

A card is randomly selected from the standard deck. What is the probability of selecting a red card, the king of spades, or the

ace of clubs?
A: 1/2

B: 7/13

C: 27/52

D: 15/52

1 answer:

lesya [120]3 years ago

8 0

Answer:

d

Step-by-step explanation:

13 red, 1 king of spade, 1 ace of club

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Factor each expression 8+16

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3 years ago

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Solve this for Brainliest!<br><br>See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

<u>Using Pythagoras</u>

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

<u>Using quadratic formula</u>

<u /> $x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$

$x = 3 + 4\sqrt{3} = 9.928(4s.f.)$

OR

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∴ $x = 3 + 4\sqrt{3}$

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2 years ago

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ISSS THISSSSS CORRECTTT??????please help

LenaWriter [7]

Answer:

I think that is correct, sorry is i get it wrong

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3 years ago

I need help with this equation: <br><br> 12x+15=99

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Answer:

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Step-by-step explanation:

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3 years ago

In triangle abc, cos A= -0.6. Find A and Tan A

Tresset [83]

Answer:

Part 1) $A=126.87^o$

Part 2) $tan(A)=-\frac{4}{3}$

Step-by-step explanation:

we have

$cos(A)=-0.6$

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive

The angle A lie on the II Quadrant

step 1

Find the measure of angle A

$cos(A)=-0.6$

using a calculator

$A=cos^{-1}(-0.6)=126.87^o$

step 2

Find the sin(A)

we know that

$sin^2(A)+cos^2(A)=1$

substitute the value of cos(A)

$sin^2(A)+(-0.6)^2=1$

$sin^2(A)=1-0.36$

$sin^2(A)=0.64$

$sin(A)=0.8$

step 3

Find tan(A)

we know that

$tan(A)=\frac{sin(A)}{cos(A)}$

substitute the values

$tan(A)=\frac{0.8}{-0.6}$

Simplify

$tan(A)=-\frac{4}{3}$

5 0

3 years ago