Ask question

Ask question

All categories

2 years ago

8

The pentagon ABCDE is graphed on a coordinate plane with vertices A(0, 0), B(3, 5), C(3, 8), D(8, 5), and E(8, 0). What is the p

entagon's perimeter?
A. 24.0 units

B. 16.0 units

C. 27.6 units

D. 32.4 units

1 answer:

Wewaii [24]2 years ago

8 0

D because you have to calculate stuff

You might be interested in

Which of the following has a slope of negative 2 in the y-intercept of 4? A) y= -2x-4

Setler [38]

D
uses the the formula y=mx+b and m is the slope. b is the y intercept.

7 0

3 years ago

Sarah has 13 stickers. Sissy has 28 stickers. Sissy divides her stickers into 4 equal groups.

777dan777 [17]

Answer:

She gave 7 stickers.13+7=20.sarah has 20 stickers

Step-by-step explanation:

Divide 28 by 4

7 0

2 years ago

Casey likes to run. She runs an additional 1/4 mile each day. On the last day, she ran 1 1/4 miles. If she ran 1/2 mile on her f

Lyrx [107]

Three days
1 1/4 = 5/4
1/2= 2/4
2/4+1/4= 3/4 the first day
5/4-3/4= 2/4
2/4 = 1/4 and 1/4 = two days
the first day+ two days= 3 days

3 0

3 years ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

3 years ago

Renaming improper fractions as whole or mixed numbers 17-4

murzikaleks [220]

17/4 as a mixed fraction would be 4 1/4

4 0

3 years ago