The answer is (D) <span>
I'll
show you how to set up a simple database with one table called
'recipes.' You'll be able to manage it and run simple queries on it to
find specific recipes very quickly and easily. All you need is some
rudimentary knowledge of access to get the job done.</span>
Spreadsheets are not bad for number crunching. However, if
you have lots of data, you may benefit from efficient data management tool. Replacing
spreadsheets with databases help you manage data centrally, safely and
securely. By employing a database, you can avoid making mistakes like miscounts
and data entry errors.
Learning Access can be a little bit daunting and
intimidating. Through self-dedication, one can conquer and learn to create
simple but functional database.
ANSWER: Kim has chosen a dark-colored design theme for her presentation. She should therefore choose <u>a bright </u> font color that will <u>contrast with </u>the background color.
Invented by William Oughtred in the 1600s but only used in the mid 1800s
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
