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egoroff_w [7]
2 years ago
12

write a program in C# that reads a set of integers and then finds and prints the sum of the even and odd integers?​

Computers and Technology
1 answer:
trapecia [35]2 years ago
5 0

Answer:

The program in C# is as follows:

using System;

class Prog {

 static void Main() {

   int n;

   Console.WriteLine("Number of integers: ");

   n = Convert.ToInt32(Console.ReadLine());

   int evensum = 0, oddsum = 0; int inpt;

   for(int i = 0;i<n;i++){

       inpt = Convert.ToInt32(Console.ReadLine());

       if(inpt%2==0){            evensum+=inpt;        }

       else{            oddsum+=inpt;        }

   }

    Console.WriteLine(evensum);

    Console.WriteLine(oddsum);

 }

}

Explanation:

This declares n, the number of integer inputs

   int n;

This prompts for n

   Console.WriteLine("Number of integers: ");

This gets input for n

   n = Convert.ToInt32(Console.ReadLine());

This declares and initializes the even and odd sum.

   int evensum = 0, oddsum = 0; int inpt;

This iterates through n

   for(int i = 0;i<n;i++){

This gets each input

       inpt = Convert.ToInt32(Console.ReadLine());

Check for even numbers and add,if even

<em>        if(inpt%2==0){            evensum+=inpt;        }</em>

Otherwise, add input as odd

<em>        else{            oddsum+=inpt;        }</em>

   }

Print even sum

    Console.WriteLine(evensum);

Print odd sum

    Console.WriteLine(oddsum);

 }

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vekshin1

Answer:

Explanation:

The following code is written in Python. It asks the user for an input. Then cleans the input using regex to remove all commas, whitespace, and apostrophes as well as making it all lowercase. Then it reverses the phrase and saves it to a variable called reverse. Finally, it compares the two versions of the phrase, if they are equal it prints out that it is a palindrome, otherwise it prints that it is not a palindrome. The test case output can be seen in the attached picture below.

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