Answer: A)Area=1/2bh, 1/2x12x9=1/2x108,108/2=54cm2.
B)If the base doubles the original Area doubles.
C)If both the Height and the base is doubled then the Area will Quadruple.
Step-by-step explanation:
Answer:
48
Step-by-step explanation:
Take the second derivative, utilizing quotient and chain rule.
![{g}^{'} = - \frac{8}{(2x - 1)^{3} } \\ {g''} = \frac{48}{(2x - 1)^{4} } \\ {g''(1)} = \frac{48}{(2(1) - 1)^{4} } = \frac{48}{1} = 48](https://tex.z-dn.net/?f=%20%7Bg%7D%5E%7B%27%7D%20%20%3D%20%20%20-%20%5Cfrac%7B8%7D%7B%282x%20-%201%29%5E%7B3%7D%20%7D%20%5C%5C%20%20%7Bg%27%27%7D%20%20%3D%20%20%20%5Cfrac%7B48%7D%7B%282x%20-%201%29%5E%7B4%7D%20%7D%20%20%5C%5C%20%7Bg%27%27%281%29%7D%20%20%3D%20%20%20%5Cfrac%7B48%7D%7B%282%281%29%20-%201%29%5E%7B4%7D%20%7D%20%20%3D%20%20%5Cfrac%7B48%7D%7B1%7D%20%20%3D%2048)
Answer:
7t + 8
Step-by-step explanation:
Answer:
Part 1:
or ![\frac{11}{5}-\frac{x}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B5%7D-%5Cfrac%7Bx%7D%7B5%7D)
Part 2: ![\frac{9}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B5%7D)
Step-by-step explanation:
To start things off, you must put everything on the opposite side of y so that you only have the y variable left.
In this case, put x onto the other side, making it negative since it's flipped, so you get
(since the x is negative you're using subtraction from 11).
Next, divide both sides by 5 to make 5y into y:
![\frac{5y}{5} =\frac{11}{5}-\frac{x}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B5y%7D%7B5%7D%20%3D%5Cfrac%7B11%7D%7B5%7D-%5Cfrac%7Bx%7D%7B5%7D)
![y=\frac{11}{5}-\frac{x}{5}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B11%7D%7B5%7D-%5Cfrac%7Bx%7D%7B5%7D)
Then in this case you turn y=f(x), but the system did it for you, so all you have to put is
.
For the second part you must replace x with 2 since you need to find f(2).
![\frac{11-2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B11-2%7D%7B5%7D)
Your answer for part 2 is
.