Answer: 4 horas
Step-by-step explanation:
Una semana (de lunes a viernes) contiene 5 días
Si se entrena 1 hora por día:
1 x 5 = 5 horas (total de horas de entrenamiento de lunes a viernes)
Ese total más el número de horas que se entrena el sábado (x) dividido por 6 (numero de días en la semana incluyendo sábado) debe ser igual a el promedio de horas entrenadas en los 6 días (1.5)
(5+x) /6 =1.5
Despajando x:
5+x =1.5 x 6
5+x =9
x =9-5
x = 4 horas
I saw the figure of the fishpond. It composed of a rectangle and a circle. The circle is cut into two and each half is attached to the width of the rectangle making an oblong shaped fishpond.
Length of the rectangle: 2.5 inch
Width of the rectangle and diameter of the circle: 1 inch
1/2 inch equals 15 feet.
2.5 inches = 75 feet
1 inch = 30 feet
Area of a rectangle = 75 ft * 30 ft = 2,250 ft²
Area of a circle = 3.14 * (15ft)² = 3.14 * 225ft² = 706.50 ft²
Total Area = 2,250 ft² + 706.50 ft² = 2,956.50 ft²
Answer:
176 cm
Step-by-step explanation:
45 degrees is what fraction of the circle
45/360 = 1/8
So multiply the arc length by 8 to get the circumference of the entire circle
22* 8 =176 cm
Answer: y = 4x
Step-by-step explanation: Slope intercept form is y = mx + b where m is the slop and b is the x intercept
We can solve for slope using the given points
(2-1)/(8-4) = 1/4, thus m = 1/4
y = 1/4x +b
Now to solve for b, we can just plug in one of the points to see what makes b work
1 = 4*(1/4) + b
1 = 1 +b
b = 0
Answer:
Yes
Step-by-step explanation:
You can get there a couple of ways. One makes use of the secant rules that tell you ...
PQ × PR = PS × PT
Substituting for PR and PT, you have ...
PQ × (PQ + QR) = PS × (PS + ST)
PQ² + PQ×QR = PS² + PS×ST
Substituting PQ for PS everywhere, we have ...
PQ² + PQ×QR = PQ² + PQ×ST
Dividing by PQ gives ...
PQ + QR = PQ + ST
and subtracting PQ leads us to the conclusion ...
QR = ST
_____
Another way to look at it is to draw the chord QS. Then ΔQPS is an isosceles triangle, and the perpendicular bisector of QS bisects ∠P and also goes through the circle center. Then the figure is symmetrical about that diameter secant, making QR ≅ ST.