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sergeinik [125]
2 years ago
12

If 10% off is 20 what is 23% off?

Mathematics
2 answers:
stepan [7]2 years ago
7 0
23% off is 46 because 10%is 20 so 20% is 40 and 1% is 2 because 20/10 is 2 so the answe is 46
N76 [4]2 years ago
5 0
It would be 46
The person who answered is correct
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The model represents a polynomial of the form ax2 + bx + c. Which equation is represented by the model?
Maru [420]

Consider the given table.

  • The first row represents first term (first brackets):

                                +x+x+x-1=3x-1

  • The first column represents second term (second brackets):

                                +x-1=x-1

  • The product of (3x-1) and (x-1) is equal to the sum of all remaining terms in this table:

                               +x²+x²+x²-x-x-x-x+1=3x²-4x+1.

Therefore, 3x²-4x+1=(3x-1)(x-1).

Answer: correct choice is C.

5 0
3 years ago
Read 2 more answers
A spinner is numbered from 1 through 10 with each number equally likely to occur. What is the probability of obtaining a number
emmainna [20.7K]

Answer:

i believe its 5/10 or 1/2

Step-by-step explanation:

5 0
2 years ago
Consider an experiment that consists of recording the birthday for each of 20 randomly selected persons. Ignoring leap years, we
8_murik_8 [283]

Answer:

a)  p_{20d} = 0.588

b) 23

c) 47

Step-by-step explanation:

To find a solution for this question we must consider the following:

If we’d like to know the probability of two or more people having the same birthday we can start by analyzing the cases with 1, 2 and 3 people

For n=1 we only have 1 person, so the probability  p_{1} of sharing a birthday is 0 (p_{1}=0)

For n=2 the probability p_{2} can be calculated according to Laplace’s rule. That is, 365 different ways that a person’s birthday coincides, one for every day of the year (favorable result) and 365*365 different ways for the result to happen (possible results), therefore,

p_{2} = \frac{365}{365^{2} } = \frac{1}{365}

For n=3 we may calculate the probability p_{3} that at least two of them share their birthday by using the opposite probability P(A)=1-P(B). That means calculating the probability that all three were born on different days using the probability of the intersection of two events, we have:

p_{3} = 1 - \frac{364}{365}*\frac{363}{365} = 1 - \frac{364*363}{365^{2} }

So, the second person’s birthday might be on any of the 365 days of the year, but it won’t coincide with the first person on 364 days, same for the third person compared with the first and second person (363).

Let’s make it general for every n:

p_{n} = 1 - \frac{364}{365}*\frac{363}{365}*\frac{362}{365}*...*\frac{(365-n+1)}{365}

p_{n} = \frac{364*363*362*...*(365-n+1)}{365^{n-1} }

p_{n} = \frac{365*364*363*...*(365-n+1)}{365^{n} }

p_{n} = \frac{365!}{365^{n}*(365-n)! }

Now, let’s answer the questions!

a) Remember we just calculated the probability for n people having the same birthday by calculating 1 <em>minus the opposite</em>, hence <em>we just need the second part of the first calculation for</em> p_{n}, that is:

p_{20d} = \frac{364}{365}*\frac{363}{365}*\frac{362}{365}*...*\frac{(365-20+1)}{365}

We replace n=20 and we obtain (you’ll need some excel here, try calculating first the quotients then the products):

p_{20d} = 0.588

So, we have a 58% probability that 20 people chosen randomly have different birthdays.

b) and c) Again, remember all the reasoning above, we actually have the answer in the last calculation for pn:

p_{n} = \frac{365!}{365^{n}*(365-n)! }

But here we have to apply some trial and error for 0.50 and 0.95, therefore, use a calculator or Excel to make the calculations replacing n until you find the right n for p_{n}=0.50 and p_{n}=0.95

b) 0.50 = 365!/(365^n)*(365-n)!

n           p_{n}

1              0

2           0,003

3           0,008

….           …

20           0,411

21           0,444

22           0,476

23           0,507

The minimum number of people such that the probability of two or more of them have the same birthday is at least 50% is 23.

c) 0.95 = 365!/(365^n)*(365-n)!

We keep on going with the calculations made for a)

n             p_{n}

…                …

43            0,924

44            0,933

45            0,941

46            0,948

47            0,955

The minimum number of people such that the probability of two or more of them have the same birthday is at least 95% is 47.

And we’re done :)

6 0
4 years ago
A student runs 100 meters in 11 seconds. What is the speed of the student? speed = distance over time; 1 mile = 1609 meters
elena-14-01-66 [18.8K]
S=D/T D=100m T=11 100/11=9.1m/s^2
7 0
3 years ago
1. 5 Burgers and 3 orders of fries cost $34. 4 Burgers and 4 orders of fries cost $32. How much does each burger and each order
Elena L [17]

Answer:

1.

a burger costs $5

an order of fries costs $3

2.

7 pennies

14 nickels

23 dimes

Step-by-step explanation:

x = price of a burger

y = price of a order of fries

5x + 3y = 34

4x + 4y = 32

=>

x + y = 8

x = 8-y

5×(8-y) + 3y = 34

40 - 5y + 3y = 34

-2y = -6

y = $3

x = 8 - 3 = $5

x = number of pennies

y = number of nickels

z = number of dimes

0.01×x + 0.05×y + 0.1×z = 3.07

y = 2x

x + y + z = 44

x + 2x + z = 44

3x + z = 44

z = 44 - 3x

0.01×x + 0.05×2x + 0.1×z = 3.07

0.11×x + 0.1×z = 3.07

0.11×x + 0.1×(44-3x) = 3.07

11x + 10×(44-3x) = 307

11x + 440 - 30x = 307

-19x = -133

x = 7

y = 2×7 = 14

z = 44 - 3×7 = 44 - 21 = 23

7 0
3 years ago
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