the graph of a liner relationship has a slope of -5 and passes through the point (2, -12). write tge equation of the liner in th
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The answer is the second graph.
You need to isolate x, in order to do this you need to multiply both sides by 3, or 3/1
2*3 = 6
x/3 * 3 = x
Your equation should now be
So the circle should be filled in and pointing towards the left starting from 6
You need to isolate x, in order to do this you need to multiply both sides by 3, or 3/1
2*3 = 6
x/3 * 3 = x
Your equation should now be
So the circle should be filled in and pointing towards the left starting from 6