5 mph to get that answer you use the speed equation
speed(mph)=distance(in miles)/time(in hours)
2.5
------ = 5 mph
.5
Answer:
why thank you :)
hope that continues for you and have an awesome day
The response variable in the study that Ann has done here can be said to be Time spent exercising.
<h3>What is a response variable?</h3>
This is the name that is used to refer to the dependent variable. This is the variable that is of interest in the study. The goal is to see the changes that occurs in the particular variable based on the actions that another variable would have such as the independent variable.
From this we can see that The response variable in the study that Ann has done here can be said to be Time spent exercising.
Read more on response variable here:
brainly.com/question/22046153
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Answer:
To figure out if 2 lines are parallel, compare their slopes. You can find the slope of a line by picking 2 points with XY coordinates, then put those coordinates into the formula Y2 minus Y1 divided by X2 minus X1. Calculate the slope of both lines. If they are the same, then the lines are parallel.
Step-by-step explanation:
To figure out if 2 lines are parallel, compare their slopes. You can find the slope of a line by picking 2 points with XY coordinates, then put those coordinates into the formula Y2 minus Y1 divided by X2 minus X1. Calculate the slope of both lines. If they are the same, then the lines are parallel.
<span>Probability = 0.063
Fourth try = 0.0973
Let X be the number of failed attempts at passing the test before the student passes. This
is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7
and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p)
xp.
The probability P that the student passes on the third try means that there were x = 2
failed attempts or P = nb(2, ; 1, .7) = (.3)2
(.7) = 0.063 . The probability that the student
passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤
2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0
(.7) + (.3)1
(.7) + (.3)2
(.7) = 0.973 .</span>
