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3 years ago

Need help.Pleaseeeee

Mathematics

1 answer:

Marina CMI [18]3 years ago

8 0

Answer:

The first one and the last one

Step-by-step explanation:

To sub x>0 and x<0 into every functions.

Then, u will get some function that y doesn't have a negative value or positive value.

Then, these function doesn't fulfill the range.

Then, u will get the answer.

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Select the expression that is equivalent<br> to 4.1.d.d.d.

Molodets [167]

? I’m confused is there supposed to be a picture to this? I don’t see a expression so..

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3 years ago

What is the explicit formula for this sequence?

ddd [48]

Answer:

$a_n=-7+4(n-1)$

$a_n=-7+(n-1)(4)$

Step-by-step explanation:

-7,-3,1,5,... is a arithmetic sequence.

Arithmetic sequences have a common difference. That is, it is going up by 4 each time.

When you see arithmetic sequence, you should think linear equation.

The point-slope form of a line is $y-y_1=m(x-x_1)$ .

m is the common difference, the slope.

Any they are using the point at x=1 in the point slope form. So they are using (1,-7).

So let's put this into our point-slope form:

$y-(-7)=4(x-1)$

$y+7=4(x-1)$

Subtract 7 on both sides:

$y=-7+4(x-1)$

So your answer is

$a_n=-7+4(n-1)$

6 0

3 years ago

Does anyone know evaluate version

exis [7]

Answer: 6

Step-by-step explanation:

6x6x6 =216

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2 years ago

Cody must complete 125 credit hours of instruction. If he has completed 60% of his requirement, how many credits did Cody comple

umka2103 [35]

You must figure out what is 60% of 125

to find the answer all you need to do is multiply 125 by 0.6

Cody completed 75 hours

i hope this helps!!

6 0

3 years ago

Show that if x and y may both be written as the sum of the squares of two rational integers, then their product xy may also be w

Georgia [21]

Answer:

See proof below

Step-by-step explanation:

One way to solve this problem is to "add a zero" to complete the required squares in the expression of xy.

Let $x=m^2+n^2$ and $y=l^2+k^2$ with $m,n,l,k\in \mathbb{Z}$ . Multiplying the two equations with the distributive law and reordering the result with the commutative law, we get $xy=(m^2+n^2)(l^2+k^2)=m^2l^2+m^2k^2+n^2l^2+n^2k^2=n^2l^2+m^2k^2+m^2l^2+n^2k^2$

Now, note that $0=2lkmn-2lkmn=2nkml-2nlmk$ by the commutativity of rational integers. Add this convenient zero the the previous equation to obtain $xy=n^2l^2-2nlmk+m^2k^2+m^2l^2+2nkml+n^2k^2=(nl-mk)^2+(ml+nk)^2$ , thus xy is the sum of the squares of $nl-mk,ml+nk\in \mathbb{Z}$ .

7 0

3 years ago