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2 years ago

Gio plotted the following points on the coordinate plane below. R(-3.5,0), S(2.5,1.5), T(-4.5,-2.5), U(2.-3.5), V(-4,-3.5)

Mathematics

1 answer:

Brrunno [24]2 years ago

5 0

Answer:

point T only.

Step-by-step explanation:

for more info see the attachment.

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Find the curl of ~V ~V = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

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3 years ago

Can someone help me with how to show the work.

mylen [45]

Answer:

x=2

Step-by-step explanation:

you can see explanation as attached file

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3 years ago

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Which ratio is smaller 8 to 2 or 10 to 1

GalinKa [24]

Simplify the ratio 8 to 2 to be 4 to 1

Now compare 4 to 1 and 10 to 1

4 is smaller than 10 so the ratio 8 to 2 is smaller.

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3 years ago

Quadrilateral ABCD is inscribed in this circle.

Anna [14]

A quadrilateral, has 4 sides and its internal angles sum, add up to 360, now... you have 3 angles give.. .but we don't have C

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so.... now once we know what C is

you can if you want, do a search in google for "inscribed quadrilateral conjecture", I can do a quick proof if you need one

but in short, for a quadrilateral inscribed in a circle, each pair of opposites angles are "supplementary angles", namely they add up to 180°

so.. what the dickens does all that mean? well D+B=180 and A+C = 180

now. we know what A is, 2x+1
and by now, you'd know what C is from 360-x-2x-1-148

so... add them together then and

$\bf \begin{array}{cccclllll}
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Debora [2.8K]

The answer is easy
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