Question

²-6x +10 is to be written in the form (x-p)² +g. Find the values of p and q.​

Answer 1

Answer:

$p = 3\\\\q= 1$

Step-by-step explanation:

$x^2 -6x +10\\\\=x^2 -2 \cdot 3x +3^2 -3^2 +10\\\\=(x-3)^2 -9+10\\\\=(x-3)^2 +1\\\\\text{By comparing with}~ (x-p)^2 +q, \\\\p = 3\\\\q = 1$